s is 938 MeV. It in GeV with 2 significant figures.

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In the laboratory frame, a proton (p) with total energy E collides with a proton at rest. Find the minimum proton energy such that the process p+p → p+p+p+pis kinematically allowed. (p
= antiproton)
The proton mass is 938 MeV.
Quote your result in GeV with 2 significant figures.
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Transcribed Image Text:In the laboratory frame, a proton (p) with total energy E collides with a proton at rest. Find the minimum proton energy such that the process p+p → p+p+p+pis kinematically allowed. (p = antiproton) The proton mass is 938 MeV. Quote your result in GeV with 2 significant figures. Answer:
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