Determine the acceleration of the cable drawn into the motor to make the load B attain a speed of 8 m.s1 in 3 s. A C В

mass of pulley = 0

OK, one more time. This time the magnet has mass 7.49 kg and the force pulling it to the right is 156.6 N. When themagnet hits the floor, it continues being pulled to the right by the same magnetic force as before. The coefficient ofkinetic friction between the magnet and the floor is 0.341. What will the magnets acceleration be as It slides to the rightalong the floor? (Assume static friction is overcome and the magnet will slide.)A) 12.29 m/s^2B) 8.4 m/S^2C) 11.56 m/S^2D) 8.78 m/S^2

A skier starts from rest at the top of a 30o incline and slides down  100 m to the bottom of the  incline.  If the coefficient of friction  between the incline (snow) and the skier is 0.2, find the speed of  the skier when he reaches the bottom of the incline. A.) 25.3 m/s B.) 6.7 m/s C.) 35.4 m/s D.) 16.7 m/s

The force needed to get a block moving and to just barely keep it moving were used to calculate the coefficient of static friction and the coefficient of kinetic friction for the block. Which values are most likely the correct ones for this block? O .35 for coefficient of static friction and .35 for coefficient of kinetic friction 25 for coefficient of static friction and .35 for coefficient of kinetic friction 35 for coefficient of static friction and .25 for coefficient of kinetic friction 25 for coefficient of static friction and .25 for coefficient of kinetic friction

Determine the magnitude of the force in cable AB so that the force in cables AD and AC is half the value of the force in cable AB.

Thanks!

Pls help ASAP! Show all work for a) b) and c) pls

A pendulum is 0.850 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob’s speed is 1.60 m/s. A) What is the tension in the string at the bottom of the swing? in N B)The tension is greater than the weight of the bob because a- its horizontal component is increasing from zero.   b-the bob has a downward acceleration, so the net Fy must be downward.   c- the bob has an upward acceleration, so the net Fy must be upward.   d- the bob has zero acceleration.

10. Consider the complicated arrangement below: de moni eosd altods beoga aldsso booe m m2 ivomoe A k of The coefficient of friction between m1 and the plane is µ1 and between m2 and the plane is µ2. Assuming a massless, unstretchable string and a frictionless pulley, obtain the relationship between the variables that determines which mass goes up and which goes down.