Return a list containing all pairs of distinct elements that satisfy the function fn. We say the pair [a, b] satisfies a function fn when calling fn(a, b) returns True. Also note that the pair [1, 1] should never be included in the final pairing since its elements are not distinct. For example, all the possible pairs with disinct elements of [1, 2, 3] are [1, 2], [1, 3], [2, 1], [2, 3], [3, 1], [3, 2] but only [1, 2], [2, 1], [2, 3], [3, 2] satisfy the condition that the sum of their elements is odd. Assume that all elements of 1st are distinct.

Assume that the nodes of the singly linked lists are arranged in decreasing order of the exponents of the variable x in order to add the two polynomials.The objective is to create a fresh list of nodes that represents the addition of P1 and P2. This is done by adding the COEFF fields of nodes in lists P1 and P2 that have identical powers of variable x, and then making a new node in the resulting list P1 + P2. The key part of the technique is shown below.The start pointers of the singly linked lists that correspond to the polynomials P1 and P2 are P1 and P2, respectively. Two temporary pointers, PTR1 and PTR2, are created with starting values of P1 and P2, respectively. Make procedural code.

Suppose you have an array-based implementation of a linked list. What would be the worst case asymtotic runtime of the following functions? Select the tightest. Please explain for each funtion. insert() search() delete() minimum() maximum()

There are two n-element arrays A and B the task is to permute them such that A[i]+b[i]>=k Can someone walk me through the code. I dont understand the iList and jList and why we have if j and i not in List we do List.append. Also at the end why we do if len(iList)+len(jList)==len(A)+len(B) ? def twoArrays (k, A, B): A.sort() B. sort() iList = [] jList = [] for i in range (len (A)): for j in range (len (B)): if(A[i]+B[j]>=k): if j not in jList and i not in iList: iList.append(i) jList.append(j) print (iList) print (jList) if(len (iList) + len(jList) ==len (A) + len(B)) return "YES" else: return "NO"

Consider the following function:int enigma(NodeInt32* node){if(node == NULL)return 0; elsereturn 1 + enigma(node->next);} Which best describes the enigma function?A. The function performs a binary search of a list. B. The function computes the length of a list. C. The function sorts a list. D. None of the above.

Python Please Define a function max_run(lst: list) -> int to find the maximum run in a list. A run is a subsequence with identifical values. For example, in [1, 1, 2, 2, 3, 4, 4, 4, 2, 4, 4], the runs are [1, 1], [2, 2], [3], [4, 4, 4], [2], and [4, 4]. The longest run is [4, 4, 4], which has 3 elements. max_run([1, 1, 2, 2, 3, 4, 4, 4, 2, 4, 4]) should return 3. max_run([]) == 0, max_run([1, 2, 3]) = 1, and max_run([1, 2, 1, 1]) = 2.

Given a singly linked list of integers, reverse the nodes of the linked list 'k' at a time and return its modified list. 'k' is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of 'k,' then left-out nodes, in the end, should be reversed as well.Example :Given this linked list: 1 -> 2 -> 3 -> 4 -> 5 For k = 2, you should return: 2 -> 1 -> 4 -> 3 -> 5 For k = 3, you should return: 3 -> 2 -> 1 -> 5 -> 4 Note :No need to print the list, it has already been taken care. Only return the new head to the list. Input format :The first line contains an Integer 't' which denotes the number of test cases or queries to be run. Then the test cases follow. The first line of each test case or query contains the elements of the singly linked list separated by a single space. The second line of input contains a single integer depicting the value of 'k'. Remember/Consider :While specifying the list…