A parallel plate capacitor of capacitance 5.19 μF has the space between the plates filled with a slab of glass with κ = 3.00. The capacitor is charged by connecting it to a 1.20-V battery. After the capacitor is disconnected from the battery, the dielectric slab is removed. X = 1.20 V. Find the energy stored in the capacitor after the glass is removed. μJ Required informationA parallel plate capacitor of capacitance 5.19 µF has the space betweenthe plates filled with a slab of glass with K = 3.00. The capacitor ischarged by connecting it to a 1.20-V battery. After the capacitor isdisconnected from the battery, the dielectric slab is removed.XV(1)GlassX = 1.20 V.Find the energy stored in the capacitor after the glass is removed.

Step 1:Step 2:Step 3:So, the energy stored in the capacitor is 11.21 μJ

Required information A parallel plate capacitor of capacitance 5.19 µF has the space between the plates filled with a slab of glass with K = 3.00. The capacitor is charged by connecting it to a 1.20-V battery. After the capacitor is disconnected from the battery, the dielectric slab is removed. XV (1) Glass X = 1.20 V. Find the energy stored in the capacitor after the glass is removed.

Required information A parallel plate capacitor of capacitance 5.19 µF has the space between the plates filled with a slab of glass with K = 3.00. The capacitor is charged by connecting it to a 1.20-V battery. After the capacitor is disconnected from the battery, the dielectric slab is removed. XV (1) Glass X = 1.20 V. Find the energy stored in the capacitor after the glass is removed.

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Capacitance And Dielectrics

Section: Chapter Questions

Problem 1P: (a) When a battery is connected to the plates of a 3.00-F capacitor, it stores a charge of 27.0 C....

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