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Start V₁ = 0 h = 25 m h = 20 m Finish v = ? Problem 12 A rollercoaster cart is gently nudged over the top of a hill, causing it to roll through a dip before flattening out (as in the diagram above). If the cart's speed at the very top of the hill is taken to be 0 m/s and the track is frictionless, what will be the cart's speed along the flat section of the track, 20 m below the top of the hill? Remember, g = 9.8 m/s². Don't forget units!

Start V₁ = 0 h = 25 m h = 20 m Finish v = ? Problem 12 A rollercoaster cart is gently nudged over the top of a hill, causing it to roll through a dip before flattening out (as in the diagram above). If the cart's speed at the very top of the hill is taken to be 0 m/s and the track is frictionless, what will be the cart's speed along the flat section of the track, 20 m below the top of the hill? Remember, g = 9.8 m/s². Don't forget units!

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Start V₁ = 0 h = 25 m h = 20 m Finish v = ? Problem 12 A rollercoaster cart is gently nudged over the top of a hill, causing it to roll through a dip before flattening out (as in the diagram above). If the cart's speed at the very top of the hill is taken to be 0 m/s and the track is frictionless, what will be the cart's speed along the flat section of the track, 20 m below the top of the hill? Remember, g = 9.8 m/s². Don't forget units!
Transcribed Image Text:Start V₁ = 0 h = 25 m h = 20 m Finish v = ? Problem 12 A rollercoaster cart is gently nudged over the top of a hill, causing it to roll through a dip before flattening out (as in the diagram above). If the cart's speed at the very top of the hill is taken to be 0 m/s and the track is frictionless, what will be the cart's speed along the flat section of the track, 20 m below the top of the hill? Remember, g = 9.8 m/s². Don't forget units!
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