Fundamentals of Geotechnical Engineering (MindTap Course List)
Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Refer to the figure below. Given: L₁ = 4m, L2 = 8 m, l₁ = l2 = 2 m, y = 16 kN/m³, Ysat = 18.5 kN/m³, and ' = 26°. Use the charts presented below the answer fields.
Sand
c' = 0
Anchor
L₁
Water table
Sand
Ysat
c' 0
$'
Sand
c' = 0
1. Determine the theoretical depth of penetration.
(Enter your answer to two significant figures.)
D=
m
2. Determine the anchor force per unit length.
(Enter your answer to two significant figures.)
F=
kN/m
3. Determine the maximum moment in the sheet pile.
(Enter your answer to two significant figures.)
CDL₁
Mmax =
0.5
kN-m/m
0.4-
-24= &'
26°
0.3
-28°
30°
32°
0.2
34°
36°
38°
0.1
0.0
0.1
0.2
0.3
0.4
0.5
1.18
1.16
1.14
1.12
1.10
1.08
1.06
1.04
4₁/(L₁+ L₂2)
L₁
4₁+12
0.3
0.2
= 0.4
expand button
Transcribed Image Text:Refer to the figure below. Given: L₁ = 4m, L2 = 8 m, l₁ = l2 = 2 m, y = 16 kN/m³, Ysat = 18.5 kN/m³, and ' = 26°. Use the charts presented below the answer fields. Sand c' = 0 Anchor L₁ Water table Sand Ysat c' 0 $' Sand c' = 0 1. Determine the theoretical depth of penetration. (Enter your answer to two significant figures.) D= m 2. Determine the anchor force per unit length. (Enter your answer to two significant figures.) F= kN/m 3. Determine the maximum moment in the sheet pile. (Enter your answer to two significant figures.) CDL₁ Mmax = 0.5 kN-m/m 0.4- -24= &' 26° 0.3 -28° 30° 32° 0.2 34° 36° 38° 0.1 0.0 0.1 0.2 0.3 0.4 0.5 1.18 1.16 1.14 1.12 1.10 1.08 1.06 1.04 4₁/(L₁+ L₂2) L₁ 4₁+12 0.3 0.2 = 0.4
CML₁
GM
CFL₁
1.04
0.16
0.0
0.1
0.2
0.1
0.3
0.4
0.5
4/(L₁+12)
0.14
-24 = &'
0.12
-26°
0.10
28°
30°
0.08
32°
34°
36°
0.06-
38°
0.04
0.0
0.1
0.2
0.3
0.4
0.5
4/(L₁+L₂)
1.08
1.07
1.06
1.05
1.04
0.3
L₁
-0.2
-0.1
= 0.4
1.03
0.0
0.1
0.2
0.3
0.4
0.5
4/(4+1)
0.05
0.04-
0.03-
0.02-
0.01-
32°
34°
36°
38°
0.00
0.0
0.1
0.2
1.06
1.04
1.02
1.00
0.98
0.96
0.3
4/(4₁+42)
0.4
24 = &'
26°
28°
30°
L₁
4₁+42
= 0.4
0.1
0.94
0.0
0.1
0.2
4₁/(L₁+ L₂)
0.3
0.1
0.2
0.3
0.4
0.5
expand button
Transcribed Image Text:CML₁ GM CFL₁ 1.04 0.16 0.0 0.1 0.2 0.1 0.3 0.4 0.5 4/(L₁+12) 0.14 -24 = &' 0.12 -26° 0.10 28° 30° 0.08 32° 34° 36° 0.06- 38° 0.04 0.0 0.1 0.2 0.3 0.4 0.5 4/(L₁+L₂) 1.08 1.07 1.06 1.05 1.04 0.3 L₁ -0.2 -0.1 = 0.4 1.03 0.0 0.1 0.2 0.3 0.4 0.5 4/(4+1) 0.05 0.04- 0.03- 0.02- 0.01- 32° 34° 36° 38° 0.00 0.0 0.1 0.2 1.06 1.04 1.02 1.00 0.98 0.96 0.3 4/(4₁+42) 0.4 24 = &' 26° 28° 30° L₁ 4₁+42 = 0.4 0.1 0.94 0.0 0.1 0.2 4₁/(L₁+ L₂) 0.3 0.1 0.2 0.3 0.4 0.5
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