Red eyes is the wild-type phenotype in Drosophila, and severaldifferent genes (with each gene existing in two or more alleles) affect eye color. One allele causes purple eyes, and a different allelecauses vermilion eyes. The purple and vermilion alleles are recessive to red eye color. Two types of crosses provided thefollowing data:Cross 1: Males with vermilion eyes × females with purple eyes354 offspring, all with red eyesCross 2: Males with purple eyes × females with vermilion eyes212 male offspring with vermilion eyes221 female offspring with red eyesExplain the pattern of inheritance based on these results. Whatadditional crosses might you make to confirm your hypothesis?

Red eyes is the wild-type phenotype in Drosophila, and severaldifferent genes (with each gene existing in two or more alleles) affect eye color. One allele causes purple eyes, and a different allelecauses vermilion eyes. The purple and vermilion alleles are recessive to red eye color. Two types of crosses provided thefollowing data:Cross 1: Males with vermilion eyes × females with purple eyes354 offspring, all with red eyesCross 2: Males with purple eyes × females with vermilion eyes212 male offspring with vermilion eyes221 female offspring with red eyesExplain the pattern of inheritance based on these results. Whatadditional crosses might you make to confirm your hypothesis?

Name: Red eyes is the wild-type phenotype in Drosophila, and severaldifferen
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Description: Red eyes is the wild-type phenotype in Drosophila, and severaldifferent genes (with each gene existing in two or more alleles) affect eye color. One allele causes purple eyes, and a different allelecauses vermilion eyes. The purple and vermilion alle

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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When Calvin Bridges observed a large number of offspring from a cross of white-eyed female Drosophila tored-eyed males, he found very rare white-eyed femalesand red-eyed males among the offspring. He was ableto show that these exceptions resulted from nondisjunction, such that the white-eyed females had received twoXs from the egg and a Y from the sperm, while thered-eyed males had received no sex chromosome fromthe egg and an X from the sperm. What progeny wouldhave arisen from these same kinds of nondisjunctionalevents if they had occurred in the male parent? Whatwould their eye colors have been?
Coat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Which of the following is the most probable interaction between the two genetic loci, A and C, based on the average F1 ratio results? A - The two loci show an epistatic pattern with the loci C epistatic to loci A. B - The two loci show a codominant pattern with both loci affecting coat color. C - The two loci interact in a Mendelian pattern with A being completely dominant over C. D - The two loci show an incomplete dominance pattern with neither loci A nor C being dominant.
Coat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Which of the following is the most probable interaction between the two genetic loci, A and C, based on the average F1 ratio results? A - The two loci show an epistatic pattern with the loci C epistatic to loci A.B - The two loci show a codominant pattern with both loci affecting coat color.C - The two loci interact in a Mendelian pattern with A being completely dominant over C.D - The two loci show an incomplete dominance pattern with neither loci A nor C being dominant.
In corn, a colored aleurone is due to the presence of an R allele; r/r is colorless. Another gene controls the color of the plant, with g/g being yellow and G_being green. A plant of unknown genotype is test-crossed, and the following progeny plants were obtained. Colored green 89 Colored yellow 13 Colorless green 9 Colorless yellow 92 What was the phenotype and genotype of the plant used for the test cross? A. Colorless green - rG/rg B. Colorless yellow - rg/rg C. Colored yellow - Rg/rg D. Colored green - RG/rg
Punnett Square for a Dihybrid Cross to Investigate Coat Colour in Mice be Вс BbCc Answer: D Ova BBCC BbCc bc) bb Cc (BC) BbCC D BbCc Bbcc X BBCC bbcc BBcc bbcc Bb Cc BC O Sperm BbCC Bb Cc Bbcc bc BBCC bbcc Вс BbCc Legend Black Brown White Coat colour in mice is controlled by the interaction of two genes. Three phenotypes result: black coat, brown coat, and white coat. The expected phenotypic ratio resulting from a cross between a bbCc female mouse and BbCc male mouse, is black: brown : white Enter only the number values in the order black brown white (Do not include spaces, commas, etc.)
Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w) and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white eyes traits. The cross was carried to an F2 progeny and only male offspring were tallied. Based on the data shown here, a genetic map was constructed. a) Diagram the genotypes of the F1 parents. b) Construct a map, assuming the white is at locus 1.5 on the X-chromosome. Phenotype Male offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0
Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w) and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white eyes traits. The cross was carried to an F2 progeny and only male offspring were tallied. Based on the data shown here, a genetic map was constructed. a) Diagram the genotypes of the F1 parents. b) Construct a map, assuming the white is at locus 1.5 on the X-chromosome *******ANSWER PART B NOT PART A!!!! Phenotype Male offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11
The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of asecond independent gene turns the pigment to purple,but its recessive allele leaves it red. A fly producing nopigment has white eyes. Two pure lines were crossedwith the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypesof the parents, the F1, and the F2.
In Drosophila, singed bristles (sn) and cut wings (ct) are both caused by recessive, X-linked alleles. The wild type alleles (sn+ and ct+) are responsible for straight bristles and intact wings, respectively. A female homozygous for sn and ct+ is crossed to a sn+ct male. The F1 flies are interbred. The F2 males are distributed as follows: genotype number sn ct 15 sn ct+ 34 sn+ ct 33 sn+ct+ 18 What is the map distance between sn and ct?
The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…
In dogs, dark coat color is dominant over albino, andshort hair is dominant over long hair. Assume that theseeffects are caused by two independently assorting genes.Seven crosses were done as shown below, in which D andA stand for the dark and albino phenotypes, respectively,and S and L stand for the short-hair and long-hairphenotypes.Number of progenyParental phenotypes D, S D, L A, S A, La. D, S × D, S 88 31 29 12b. D, S × D, L 19 18 0 0c. D, S × A, S 21 0 20 0d. A, S × A, S 0 0 29 9e. D, L × D, L 0 31 0 11f. D, S × D, S 45 16 0 0g. D, S × D, L 31 30 10 10Write the genotypes of the parents in each cross. Use thesymbols C and c for the dark and albino coat-color allelesand the symbols H and h for the short-hair and long-hairalleles, respectively. Assume parents are homozygousunless there is evidence otherwise.