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- Which best describes the shape of the distribution? * Heights of U.S. Adults 80- 70- 60 50 40 30 20 10 144 152 160 168 176 184 192 CM O Camel Back Bow Tie Uniform Normal FrequencySea turtles exhibit temperature-dependent sex determination, meaning that ambient temperatures control whether or not a developing turtle embryo will become male or female. The data table reflects the numbers of turtle offspring counted in Year 1 and Year 2 of a study. Male Female Year 1 180 20 Year 2 164 33 What type of test can scientists use to assess whether or not the ratio of male to female sea turtles is dependent upon the year? O ANOVA O Chi-square contingency O 2-sample t test O Chi-square goodness of fit11.0 G. fortis 10.0- 1978 1976 9.0F 8.0 8.0 9.0 10.0 11.0 Midparent bill depth (mm) Geospiza is a genus of finches that inhabit the Galapagos Islands. In 1976, finches were grouped together based on the average depth of their bills. The data from the first generation of grouped finches are plotted on the X-axis. The bill depths of the offspring from each group are plotted on the Y-axis. In 1978, the experiment was repeated after a drought on the Galapagos Islands. The red line represents the data from 1976 and the blue line represents the data from 1978. The slope of both the red line is 0.90 and the slope of the blue line is 0.90. Was there any change in the heritability of the bill depth trait after the drought? Explain your reasoning. Offspring bill depth (mm)
- According to the figure for oppossums Birth Age (months): 0 Energy source: Energy used for: Baby Juvenile Maturity Adult Killed by predator 1st litter 2nd litter Independence (8 pups) (7 pups) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Mother Gathered by self Growth, metabolism, and repair Metabolism, repair, and reproduction delayed maturation = longer growth = larger litters early maturation = shorter growth = larger litters early maturation = shorter growth = fewer litters delayed maturation = longer growth = more littersLitter size, and calving interval can be measure in chicken. True or False80% 60% 40% 20% 10 15 20 Hatchling size(cm) What does this scatterplot indicate about the relationship between hatchling size and fish survival? they are independent of each other the relationship between them is negative the relationship between them is positive Survival rate (% fish living after 1 yr)
- 3806/variants/596276/take/13/ Tp The very long beak of a hummingbird has evolved along with the tubular flower that it pollinates. Which of the following processes explains how these 2 separate populations can change together? All Changes Saved s Answered 56°F Mostly cloudyThe table below shows 2010 census data on Ubekizakhan with the population of women and the number of births to these women by different age groups;Age of Women Number of Women Number of Children15-19 1861 52020-24 11175 146125-29 23556 2291130-34 30611 308235-39 39974 113240-44 39158 23145-49 3122 72 Assuming the country’s sex ratio at birth was 60 males per 80 females, compute the following; i) Plot a graph showing the age-specific fertility rate (ASFR) in Ubekizakhan and explain the variations.ii) General fertility rate iii) Age-specific fertility rate iv) Gross reproduction rate v) Total fertility rateinate S_Q1_Science_Biology_2022-2023 Question 1 200 TIDO D D BO 70 60 550 40 30 20 10 OF 0 5 X me graph shows the growth of the P caudatum population when it is grown separately. P. caudatum Alone 250 200 150 5 V 10 Time (days) Q Zoom 10 Time (days) 15 15 The graph shows the growth of the P. aurelia and P. caudatum populations when they are grown together. Both Species Grown Together 20 2022 Illuminate Education TM, Inc. Question 1 Which statement is supported by the graphs? A A B C D Accessibility Tools Signed in as: Zavion Ma Q Review/✔ Finish T ABG P. caudatumrand P. aurelia competed equally for resources. P. aurelia and P. caudatum did not compete for resources. P. aurelia was better able to compete for resources than P. caudatum P. caudatum was better able to compete for resources than P. aurelia Z
- A Ims.moe.gov.ae/Dashboard#!/view/328891//1027748/Activities I Managed bookmarks Chargaff's Rule Review äiglho äliwill JS - älimi 2 Below shows the amount of base percentages for given organisms. Using Chargaffs Rule, enter in the missing base percentages for 2 each organism. Please ensure to enter in all answers as a percentage (i.e. 17% not 17) Organism Adenine Cytosine Human 23% Monkey 15% Camel Dog Dolphin 33% والسابق plm alimi 2/ ailc äibul ani Jigu 0 Intro to C 8:23 11/11,WRITE DOWN SOME NOTES OR TAKE AWAYS ABOUT THIS MODEL. Model 3 – Random Genetic Drift This model is an adaptation of the classic experiment conducted by Peter Buri (1956), which documented genetic drift in laboratory populations of Drosophila. In the model, ten vials (populations) of flies are held at a constant population size and the proportions of a mutant allele are tracked over generations. The population size and the initial allele proportion can be manipulated.3796/variants/609314/take/8/ Refer to the food web at the top of the page. Which terms describe the mountain lion? Select all that apply. Food Web Wolf Mountain Lion Cat Whiptail Ringtail Pine A Marten Eagle Jackrabbit ぐ Nm! Rat Frog Butterfly Squirrel Deer Nuthatch O0 0 0 All Changes Saved wered