**Range of Ankle Motion and Compression Bandages Study***Research Context:*Range of ankle motion is a contributing factor to falls among the elderly. Researchers are studying the effect of wearing compression bandages or hosiery combined with different types of footwear on ankle motion. It is suspected that more than half of adults wearing compression bandages without shoes will experience a decrease in ankle motion by at least 2° compared to when they are barefoot without these bandages.*Study Methodology:*- A random sample of 29 adults was chosen.- 17 adults exhibited a decrease in ankle motion by at least 2°.- The sample proportion calculated is: \[ \hat{p} = \frac{17}{29} = 0.586 \]*Statistical Analysis:*To evaluate this hypothesis, a one-sample z-test was conducted with the following null and alternative hypotheses:- Null Hypothesis ($H_0$): $p = 0.500$- Alternative Hypothesis ($H_1$): $p > 0.500$where $p$ is the proportion of adults whose ankle motion decreases by at least 2° while wearing compression bandages with no shoes. - A 95% confidence interval for $p$ was computed, with a lower limit of 0.436.*Research Conclusion:*Based on the confidence interval:- The researchers concluded by choosing to "fail to reject" $H_0$ at a significance level of $ \alpha = 0.10 $.- The selection was made because the condition $0.586 > 0.436$ holds true.*Decision Justification Diagram:*The diagram provided features dropdown options used to select statistical conclusion criteria:- **Significance Level ($\alpha$) Selections:** - $\alpha = 0.10$ (selected option) - $\alpha = 0.95$ - $\alpha = 0.05$- **Comparison Selection:** - $0.586 > 0.436$ (selected option) - $0.500 > 0.436$ - $0.586 \leq 0.500$ This decision was made due to the calculated proportion 0.586 exceeding the lower confidence interval limit of 0.436.

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Answered: Range of ankle motion is a contributing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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