A-3.3% grade meets a +6.6% grade at a vertex (El, 144.37m) directly under an overpass bridge having underside elevation of 156.07 m. A 6.7 meters clearance under the bridge and the center of the curve was observed. Determine the horizontal length of curve in meters.

A 800ft vertical curve has its PVI at elevation 232.25ft. The initial and final grades are 3.7% and -5% respectively. Determine the elevation of a point 349ft from PVC.

A vertical curve parabolic curve connects a 5% and -7% grade. The point of intersections is located at station 2+100 and the elevation is 35 m. The length of the curve at the left side of the vertex is 60 m and 80 m on the other side. Determine the location of the summit.

A-3.3% grade meets a +7.4% grade at a vertex (El. 139.57m) directly under an overpass bridge having underside elevation of 150.31 m. A 6.5 meters clearance under the bridge and the center of the curve was observed. Determine the vertical clearance at the right edge of a 13.1 meters bridge from the curve in meters. ASAP!

1.) A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 240m on one side of the vertex of the straight grade and 115m on the other. The station of the beginning of the curve, PC, is 18 + 612 and its elevation is 415.81m. a. Determine the elevation at station 18 + 672. b. Determine the stationing of the lowest point of the curve.

2. There is a Vertical Curve with a length of 300 feet, a g1 of -3.2%, a g2 of 1.8%, a PVI at station 20+50.00, at an elevation of 365.92. Determine the HP/LP and elevate all even 100 foot stations and the HP / LP.

An equal tangent sag curve is designed with a PVC at station 3+320 and elevation 290m, the PVI at station 3+375 and elevation 288.74m, and the low point is at station 3+365.determine the design speed of the curve.