Question: Determine the enthalpy of formation of liquid hydrogen peroxide, H2O2, at 25°C from the following thermochemical equations: Since the equation is not given, you have to write the balanced equation to form I mol H:O: from elements! H2 (g) + ½ O2 (g)→ H20 (g) 2H (g) + ½ O2 (g) → H20 (g) 2H (g) + 2 0 (g) O2 (g) H2O2 (I) H2O2 (g) AH° = -241.82 kJ/mol AH° = -926.92 kJ/mol AH° = -1070.60 kJ/mol AH° = -498.34 kJ/mol - H2O2 (g) 20 (g) → AH° = +52.46 kJ/mol [+60.38 kJ mot')

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Question: Determine the enthalpy of formation of liquid hydrogen peroxide, H2O2, at 25°C
from the following thermochemical equations:"
11
Since the equation is not given, you have to write the
balanced equation to form I mol H;O2 from elements!
H2 (g) + ½ O2 (g) → H2O (g)
2H (g) + ½ O2 (g) → H2O (g)
2H (g) + 20 (g) → H2O2 (g)
20 (g) →
H2O2 (1) → H2O2 (g)
AH° = -241.82 kJ/mol
AH° = -926.92 kJ/mol
AH° = -1070.60 kJ/mol
O2 (g)
AH° = -498.34 kJ/mol
AH° = +52.46 kJ/mol
[+60.38 kJ mot')
Transcribed Image Text:Question: Determine the enthalpy of formation of liquid hydrogen peroxide, H2O2, at 25°C from the following thermochemical equations:" 11 Since the equation is not given, you have to write the balanced equation to form I mol H;O2 from elements! H2 (g) + ½ O2 (g) → H2O (g) 2H (g) + ½ O2 (g) → H2O (g) 2H (g) + 20 (g) → H2O2 (g) 20 (g) → H2O2 (1) → H2O2 (g) AH° = -241.82 kJ/mol AH° = -926.92 kJ/mol AH° = -1070.60 kJ/mol O2 (g) AH° = -498.34 kJ/mol AH° = +52.46 kJ/mol [+60.38 kJ mot')
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