QUESTION 8 Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function V(I,R) - IR. Your measured current and resistance have the following values and uncertainties I= 2.4 Amps, 81 = 0.2 Amps andR- 29.5 Ohms and SR = 0.6 Ohms. What is the uncertainty in the, SV ? Units are not needed in your answer.

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**Question 8**

Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function \( V(I, R) = IR \). Your measured current and resistance have the following values and uncertainties: \( I = 2.4 \) Amps, \( \delta I = 0.2 \) Amps, and \( R = 29.5 \) Ohms, and \( \delta R = 0.6 \) Ohms. What is the uncertainty in the voltage, \( \delta V \)? Units are not needed in your answer.
Transcribed Image Text:**Question 8** Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function \( V(I, R) = IR \). Your measured current and resistance have the following values and uncertainties: \( I = 2.4 \) Amps, \( \delta I = 0.2 \) Amps, and \( R = 29.5 \) Ohms, and \( \delta R = 0.6 \) Ohms. What is the uncertainty in the voltage, \( \delta V \)? Units are not needed in your answer.
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Uncertainty in the potential difference

δVV=δII+δRRδV=δII+δRRV=δII+δRRIR

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