fig 5 10tm Me= In Figure 5. the electron on the right side is fixed. and the one on the left side has initial velocity 10' m/s towards the first electron at the distance shown. Determine the final speed of the mobile electron when it is far away from the fixed one.
fig 5 10tm Me= In Figure 5. the electron on the right side is fixed. and the one on the left side has initial velocity 10' m/s towards the first electron at the distance shown. Determine the final speed of the mobile electron when it is far away from the fixed one.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 34P
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Question
why PEf is equal to 0 instead of PEi equal to 0？？？？
Transcribed Image Text:fig 5
Me=
In Figure 5. the electron on the right side is fixed. and the one on the left side has initial velocity 10' m/s towards the first electron at the distance shown.
Determine the final speed of the mobile electron when it is far away from the fixed one.
Transcribed Image Text:HWHL
5)
105 m
"fiked
Ef = Ei
KEP + PEp = KEi +PE;
ちがい銀た。
why PES =0 NOt PEi =0??
%3D
mri
2
9.1x1331xw8
= 1p° +5 x.
10-29
15-39
[Vf
10 5 mrs
qutentiy.
10:45
1311 Raom.
=2.45
Expert Solution
Step 1
Given
Initial separation between the electrons (Ri) = 10-8 m
Initial velocity of first electron = 0
initial velocity of second electron = 10 m/s
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