Question 5. You take a simple random sample of n = 49 individuals from this population and calculate the mean cholesterol of the sample. Describe the sampling distribution of .The sampling distribution of is N(190, 40)The sampling distribution o fis N(190, 5.714)The sampling distribution of is N(190, 49)The sampling distribution of is N(190, 7)Question 6. Regarding the mean derived from a sample of n = 49, what is the probability of getting a sample mean that is less than 180? [Determine Pr( ≤ 180).]0.040.400.600.96Question 4. What is the probability of selecting someone at random from this population who has a cholesterol value that is less than 180? 0.250.400.600.80

Sampling Distribution of a Normal Variable : Given a random variable X. Suppose that the population distribution of X is known to be normal, with mean µ andvariance σ2 , that is, X ~ N(µ, σ). Then, for any sample size n, it follows that the sampling distribution of X is normal,with mean µ and variance σ2 / n , that is, X¯ ~ Normal μ,σn Given , random sample size = 49 . Sampling distribution of is N(190, 40) . The following information about the mean and standard deviation has been provided: \mu = 190, \text{ } \sigma = 7, \text{ } n = 49μ=190, σ=7, n=49 We need to compute Pr ( X¯≤180 ). The corresponding z-value needed to be computed : Therefore , Probability of getting a sample mean that is less than 180 = 0.04 The following information has been provided: \mu = 190, \text{ } \sigma = 40μ=190, σ=40 We need to compute \Pr(X \leq 180)Pr(X≤180). The corresponding z-value needed to be computed: Therefore , Probability of selecting someone at random from this population who has a cholesterol value that is less than 180 = 0.040

Answered: Question 5. You take a simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Question

Question 5. You take a simple random sample of n = 49 individuals from this population and calculate the mean cholesterol of the sample. Describe the sampling distribution of .

The sampling distribution of is N(190, 40)
The sampling distribution o fis N(190, 5.714)
The sampling distribution of is N(190, 49)
The sampling distribution of is N(190, 7)

Question 6. Regarding the mean derived from a sample of n = 49, what is the probability of getting a sample mean that is less than 180? [Determine Pr( ≤ 180).]

0.04
0.40
0.60
0.96

Question 4. What is the probability of selecting someone at random from this population who has a cholesterol value that is less than 180?

0.25
0.40
0.60
0.80

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions