| AppsG GmailYouTubeMapsUST Cloud Campus Desmos | Graphing...0.034QUESTION 3ProblemA solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in thewire.L.rimageSolutiona)Let us first derive the expression for the tension.By Newton's First LawSave All AnswersClick Save and Submit to save and submit. Click Save All Answers to save all answers.29°C L ight rain Solutiona)Let us first derive the expression for the tension.By Newton's First LawΣF 0%3Dthe components of force that makes this so isΣΕSimplifying this results toT =g/(4)Analyzing the figure above, we arrive at(0) = sqrt(By substitution, we arrive at the following:T =T+ 2)g/(For Blank 13If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT = 470.3703620.370 NQUESTION 4n and cubmit Click Saue All Answers to save all answers.+

Let the tension in the string be T, the the force in vertice direction will be zero.…

Answered: QUESTION 3 Problem A solid uniform ball…

QUESTION 3 Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. image

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter7: Gravitation

Section: Chapter Questions

Problem 73A

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
ΣF 0
%3D
the components of force that makes this so is
ΣΕ
Simplifying this results to
T =
g/
(4)
Analyzing the figure above, we arrive at
(0) = sqrt(
By substitution, we arrive at the following:
T =
T+ 2
)g/(
For Blank 13
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T = 470.370362
0.370 N
QUESTION 4
n and cubmit Click Saue All Answers to save all answers.
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