QUESTION 24 A Hi-Tech company has introduced a new flash disk. Some dealers and customers have complained that some of the new disks are defective. In order to investigate this the company randomly tested n disks and found that 6.04% were defective. Find the appropriate sample size necessary to achieve a margin of error of 0.058 in order to construct a 97% confidence interval for the proportion of all flash disks that are defective. Round your answer to the nearest integer (whole number).

An educator wants to construct a 99% confidence interval for the proportion of elementary school children in Michigan who are proficient in reading. Estimate the sample size needed to conduct this survey and assume that there there is no information available to be used from a previous study. Use a margin of error of 3%.   What is the sample size:   _________

Imagine that you obtain a random sample of 125 M&M candies, and you notice that 28% of these candies are blue. If we convert the sample percentage of 0.28 to a sample proportion (by dividing 28 by 100), we get 0.28.

In the Star and Tribune newspaper, there is an article entitled "1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. How large a sample would you have to take in order to construct a 95% confidence interval estimate for the true proportion of buses that fail the inspection and achieve a margin of error of plus or minus 2%? (your answer should be an integer)

Many studies have investigated the question of whether people tend to think of an odd number when they are asked to think of a single-digit number (0 through 9; 0 is considered an even number). When asked to pick a number between 0 and 9, out of 70 students, 42 chose an odd number. In a different class of 80 students, 51 chose an odd number. A 95% confidence interval for based on these data is (0.522, 0.740), and a 99% confidence interval is (0.487, 0.766). What would be true about the p-value for testing whether a differs from 0.5? O The p-value would be less than 0.01. O The p-value would be less than 0.05 but greater than 0.01. O The p-value would be less than 0.10 but greater than 0.05. O The p-value would be greater than 0.10. O There is not enough information provided to answer this question.

Suppose a sample of 9 customers spends an average of $200 with a standard deviation $20 what is a 95% confidence interval for the sample mean. Use the fact that 95% of sample means are within 2.306 standard errors of the sample mean.

Suppose in a random sample of 246 individuals, 35 are considered success. Compute the margin of error for a 98% confidence interval for the population proportion p. Round your answer to three decimal places.

A consumer agency estimate the proportion of all drivers who wear seat belts while driving. What is the most conservative estimate of the sample size that would limit the margin of error to within 0.06 of the population proportion for a 99 % confidence interval ?