Question 20 Given the results of a standard proctor test are: Specific gravity, Gs=2.75, volume of mold=944 cm3, mass of wet soil=1,710 g, moisture content, wc=13.0 %. What is the dry unit weight of the sample compacted at this 13.0 %? (Unit: kN/m3, use two decimals in your answer)
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- Geotechnical Engineering (UPVOTE WILL BE GIVEN. PLEASE ANSWER THE QUESTION CORRECLTY. NO LONG EXPLANATION NEEDED. FOLLOW THE INSTRUCTIONS CAREFULLY.) A moist soil weighed 895 g with a volume of 425 cm3. After drying, the sample weighed 775 g. Of the dried soil, 400 g was poured into a vessel loose state. Its volume subsequently determined to be 275 cm3. That same 400 g was then vibrated and tamped to a volume of 212 cm3 with Gs = 2.71. Determine the designation of the granular soil based on its relative density. (3 decimal places - Do not round off unless it's the final answer)Geotechnical Engineering (UPVOTE WILL BE GIVEN. PLEASE ANSWER THE QUESTION CORRECLTY. NO LONG EXPLANATION NEEDED. FOLLOW THE INSTRUCTIONS CAREFULLY.) A moist soil weighed 895 g with a volume of 425 cm3. After drying, the sample weighed 775 g. Of the dried soil, 400 g was poured into a vessel loose state. Its volume subsequently determined to be 275 cm3. That same 400 g was then vibrated and tamped to a volume of 212 cm3 with Gs = 2.71. a. Determine the relative density of soil in %. b. Determine the designation of the granular soil based on its relative density.Q': A- Classification tests have been performed on a soil sample and the grading curve that shown in (Fig. 1) and Atterberg limits obtained. Classify the soil using the USCS? L.L=32 and P.L=26 100 80 60 40 20 Fig. 1 0.1 1 Particle size (mm) 0.0001 0.001 0.01 10 100 % Finer
- Laboratory sieve analysis was carried out on a soil sample using a complete set of standard IS sieves. Out of 500 g of soil used in the test, 200 g was retained on IS 600 µ sieve, 250 g was retained on IS 500 µ sieve and the remaining 50 g was retained on IS 425 µ sieve. The coefficient of uniformity of the soil isThe table shows the laboratory result of the sieve analysis of the sample. Determine the percent finer at size 0.74 and 0.004. Determine also the soil classification using AASHTO. Weight Retained 18.96 Size (mm) 0.25 0.149 0.074 0.052 0.02 33.18 45.03 54.51 42.66 0.01 11.85 0.004 0.001 Pan 4.74 4.74 21.33Following results are obtained for a liquid limit test using a fall cone device. Estimate the liquid limit of the soil and the flow index.
- (b) Classification tests for the determination of the particle size distribution of a soil produced the following results: Particle Size % finer (mm) 99 2.36 80 1.3 63 0.6 33 0.2 10 0.075 3 0.02 Then using cone penetrometer for Liquid Limit test, the results were recorded as follows. Cone penetration 15.9 17.7 19.1 20.3 22.5 (mm) Water 32.6 42.9 51.6 59.8 66.2 content (%) While the plastic limit test conducted for the same soil recorded as below:- Test No. 1 2 3 Wet soil 10.01 11.23 9.72 Dry soil 8.02 9.01 7.72 SKAA 1713 4 i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b). Calculate the uniformity coefficient, Cu and the coefficient of gradation, C, for the soil sample. Determine the plastic limit, the liquid limit and the plasticity index of the soil. Plot the graph to help you obtain the results (if necessary). ii) iii)Initial data for determining the specific gravity of a soil sample is given below: Calibration of Pycnometer (1) Mass of dry clean pycnometer, Mp= 317.11 g (2) Mass of pycnometer + water at calibration temperature, Mpw,c = 903.03 g (3) Observed temperature of water at calibration, Tc = 26.4°C Determine the calibrated volume of the pycnometer, Vp. (Units of mL, 3 decimal places) Your Answer:Q5: Determine the soil particle density of the total soil sample based on the data given Satisfactory in Table 3A, Table 3B and Table 3C. Assume that the fine fraction of the total sample was 70% and the coarse fraction of the total sample was 30%. Table 3A: Data from density bottle tests Sample number Temperature (°C) Density bottle number Mass of empty bottle, m₁ (g) Mass of bottle + dry soil, m2 Mass of bottle + soil + water, m3 (g) Mass of bottle + water, m4 (g) The apparent density of the fine fraction (g/cm³) Table 3B: Data from weighing in water tests Sample number Temperature in °C Mass of dry soil particles, m5 (g) Equivalent mass of wire basket immersed in water, m. (g) Equivalent mass of wire basket and soil particles immersed in water, m7 (9) The soil particle density of coarse fraction (g/cm³) °C 15 16 17 Density of water (p) at various temperatures g/cm³ 18 19 20 21 22 Table 3C: Variation of density of water with temperature (AS 1289.3.5.1 - 2006) 0.9991 0.9989 0.9988…
- - My courses > Soil-20-21 > Topic 3: Soil Compaction > Compaction Quiz The data in the table below was gotten from modified Proctor test for a soil sample having G,-2.62 w (%) 10 12 14 17 19 23 1.15 1.07 0.94 0.83 0.88 0.92 What is the degree of compaction if the field dry unit weight is 13.2 kN/m' and field moisture content is 9% ? O a. 71.3% Ob. 100% Oc. 94% Od. 80%The following are the data of a soil sample:Sample Size – 2-inch diameter, 4 inches high.Wet weight – 0.401 lbsOven-dry weight – 0.334 lbsSpecific Gravity – 2.68Calculate the following:a. Void Ratiob. Water contentc. Degree of SaturationFind the value of Cc of the following soil data sample Weight Percentage Cumulative Percentage Sieve Weight retained (gm) percentage retained (C) retained finer S.NO Select one: O a. 10.85 size (gm) N = (100 - C) {W,/ W,} x 100 1 75mm 100 O b. 7.36 63mm 100 O c. 18.34 50mm 100 O d. 2,96 4 37.5mm 454 22.7 22.7 77.30 5 28mm 285 14.25 36.95 63.05 6 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 2 -99.6 = 0.4 % of material 2. 3.