College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Answer the following questions A. The critical angle for total internal reflection at a diamond-air interface is 25 degrees. Suppose the light falls at an angle to the normal. Then, total internal reflection will occur if the incident medium is: a) air and angle < 25 degrees b) air and angle > 25 degrees c) air and angle = 25 degrees d) diameter and angle > 25 degrees e) diamond and angle < 25 degrees B. A ray of light in water (index n1) hits its surface (with air) at a critical angle for total internal reflection. Now some oil (index n2) floats in the water. The angle between the ray in the oil and the normal is: note: sin -1 (1.00), it is read as the inverse sine of one. a) sin -1 (1/n1) b) sin -1 (1/n2) c) sin -1 (1.00) d) sin -1 (n1/n2) e) sin -1 (n2/n1) C. A ray of light passes obliquely (non-zero angle) through a glass plate that has parallel faces. The emerging ray: a) it leans more towards the normal than the incident ray b) is reflected internally toatl c) tilts…arrow_forwardThe resolving power doubles. C. The resolving power is reduced to 1/2 of its original value. d. The resolving power is reduced to 1/4 of its original value. e The resolving power does not change unless the focal length changes. None of the above Find the angle of the refracted ray. n=2.41 23.6° 9=75.0⁰ a. b. 45.8° é [Q2] A ray of light is incident on a thick sheet of synthetic diamond (n=2.41) at an angle of 75.0°. nasina ng sine b = (2.41) Sin(75.0°) = n₂ 2.32=nb e C. 59.0° d. 75.0⁰ 98.6° None of the above f. =tan(2.33) =66/18 G en 5.00 m away. be 1.70 cm apa d=5arrow_forwardIn the figure, a 2.1-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle = 51.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. A Blocked sunraysarrow_forward
- A laser beam shines along the surface of a block of transparent material. (See the figure .) Half of the beam goes straight to a detector, while the other half travels through the block and then hits the detector. The time delay between the arrival of the two light beams at the detector is 6.10 ns. Part A What is the index of refraction of this material? n = -- ΑΣΦ Submit Request Answer ? n = ? -2.50 m- Detectorarrow_forwardA1. As shown in Figure A1, a light ray is incident normal to one face of a 30°-60°-90° prism (n = 1.50) that is immersed in water (n = 1.33). Determine the exit angle 03. (a) Determine the exit angle 03. (b) Determine the critical angle for the prism-water system. n2 60.0° n1 Figure Al 021 30.0% D 103arrow_forwarda. A ray of light enters a fiber optic cable with index of refraction n from air at an angle e as shown below. Let the angle 0 be 69°. For total internal reflection to occur at the cable-air interface, what must be the value of n? n = nair = 1 0 θα θα narrow_forward
- a. A ray of light enters a fiber optic cable with index of refraction n from air at an angle e as shown below. Let the angle 0 be 69°. For total internal reflection to occur at the cable-air interface, what must be the value of n? Dair - 1 n = Ꮎ θα ec narrow_forward1. A light ray is incident on a glass prism with refractive index 1.5 and apex angleA= 30° as shown below. Draw the path of the light ray until it emerges from the prism. Aarrow_forwardStephen is given a large crystal and needs to verify whether it is a diamond or cubic zirconia. He shines a beam of light at a 48.8 ° angle upon the face of the crystal and measures the refraction angle. What is the refraction angle if the crystal is a diamond? refraction angle for diamond - What is the refraction angle if the crystal is a cubic zirconia? refraction angle for cubic zirconia =arrow_forward
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