Question 17 of 42 The fraction of molecules with sufficient KE is given by the equation: fKE = Ae-E/RT. This fraction increases O as A increases. O as EA increases. O as Tincreases. O as Rincreases.

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
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Chapter30: Kinetic Methods Of Analysis
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Problem 30.15QAP
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T INCREASES IS WRONG

Question 17 of 42
The fraction of molecules with sufficient KE is given by the equation: fKE=Ae-E/RT. This fraction increases
as A increases.
as E increases.
O as Tincreases.
O as R increases.
Transcribed Image Text:Question 17 of 42 The fraction of molecules with sufficient KE is given by the equation: fKE=Ae-E/RT. This fraction increases as A increases. as E increases. O as Tincreases. O as R increases.
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