Question 13 of 13 For which of the following equations would the value of Kp = Kc(RT)? Note Kc is sometimes called K. A) A (g) + 2B (s) = C(s) + 2 D (g) B) 2 NO₂ (g) = N₂O4 (9) C) 2 NBr3 (g) = N₂ (g) + 3 Br₂ (g) Submit D) 2 HI (g) H₂(g) + 12 (9)

Please find the equilibrium constant (K) for reaction "3" below by using any/all of the information presented below.  Note, I will use <-> to indicate equilibrium arrows Rxn 1     2 NO(g) <-> N2(g) +O2(g)                K1= 2.1x1030 Rxn 2     2 NO(g) +Br2(g) <-> 2 NOBr(g)       K2 = 28.09 Rxn 3     N2(g) +Br2(g) +O2(g) <-> 2 NOBr(g)    K = ???

Identify the proper form of the equilibrium-constant expression for the equation N2 (g) + O2 (g) = 2NO(g) • View Available Hint(s) [NO] Ο Κ: [N2][O2] [NO]? O K: [N2][O2] 12 [N2][O2] O K = [NO]? 2[NO] Ο Κ- [N2][O2]

The question is attached below

Calculate the value of Kp for the equation C(s) + CO₂(g) 2 CO(g) given that at a certain temperature Kp Kp = ? C(s) + 2 H₂O(g)CO₂(g) + 2 H₂(g) H₂(g) + CO₂(g) H₂O(g) + CO(g) Kpl = 3.13 Kp2 = 0.625

Be sure to answer all parts. Kp = 6.5 x 104 at 308 K for the following reaction: 2 NO (g) + Cl₂(g) = 2 NOCI(g) - At equilibrium, PNO = 0.35 atm and Pcl₂ = 0.20 atm What is the equilibrium partial pressure of NOCI(g)? PNOCI X 10 atm

-2 The equilibrium constant, K, for the following reaction is 1.71x10 at 1120 K 25O₂(g) 250₂(g) + O₂(9) Calculate K, at this temperature for the following reaction SO₂(g) SO₂(g) + 1/2O₂(g)

Question 3: Now try to solve this problem. The following system is allowed to reach equilibrium: N2(g) + 202(g) = 2 NO2(g) At equilibrium, [N2] = 0.45 M, [02] = 0.80 M and [NO2] = 0.75 M. Calculate the equilibrium constant.

7 4 (a) Calculate the value of Kc for the reaction: PC15 (2) PC13 (g) + Cl2 (g) AH = Positive Given that when 8.4 mol of PCls (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PCls (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: (1) Increasing temperature (ii) Lowering the concentration of chlorine (Cl2) (iii) Addition of a catalyst

Do not give handwriting solution.