-2. Express the equilibrium constant for the following reaction. 16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g) [CH2C12]16[H2 ]8 B) K = [CH3CI]16[Cl2]8 [CH2C12][H2] A) K = TCH3CI][Cl2] [CH3C1]16[Cl2]8 C) K = [CH2C12]16[H2]8 D)K= [CH2C22][H2] [CH3CI][Cl2] [CH3CI]1/2[Cl2] E) K = [CH2C12]l/2[H2]
-2. Express the equilibrium constant for the following reaction. 16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g) [CH2C12]16[H2 ]8 B) K = [CH3CI]16[Cl2]8 [CH2C12][H2] A) K = TCH3CI][Cl2] [CH3C1]16[Cl2]8 C) K = [CH2C12]16[H2]8 D)K= [CH2C22][H2] [CH3CI][Cl2] [CH3CI]1/2[Cl2] E) K = [CH2C12]l/2[H2]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Express the equilibrium constant for the following reaction.
![-2. Express the equilibrium constant for the following reaction.
16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g)
[CH2C12]16[H2 ]8
B) K = [CH3CI]16[Cl2]8
[CH2C12][H2]
A) K = TCH3CI][Cl2]
[CH3C1]16[Cl2]8
[CH3CI][Cl2]
C) K = [CH2C12]16[H2]8 D)K= [CH2C22][H2]
[CH3CI]1/2[Cl2]
E) K = [CH2C12]l/2[H2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14a1bc80-8d3b-4bc3-9749-f72785d889ce%2Fcd7a9135-29fb-44e3-a42f-26d68661deaf%2Fzxtc5un_processed.png&w=3840&q=75)
Transcribed Image Text:-2. Express the equilibrium constant for the following reaction.
16 CH3CI(g) + 8 Cl2(g) → 16 CH2C12(g) + 8 H2(g)
[CH2C12]16[H2 ]8
B) K = [CH3CI]16[Cl2]8
[CH2C12][H2]
A) K = TCH3CI][Cl2]
[CH3C1]16[Cl2]8
[CH3CI][Cl2]
C) K = [CH2C12]16[H2]8 D)K= [CH2C22][H2]
[CH3CI]1/2[Cl2]
E) K = [CH2C12]l/2[H2]
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