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Question 11 Calculate the pH at the equivalence point for the titration of 60.7 mL of 0.574 M NH3 (Kh = 1.8 x 10-5) with 0.469 M HCI. (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation-examples include 1.23 and 120. and -123 and 123. and 12.3) A Moving to another question will save this response. Question 11 of 30

Question 11 Calculate the pH at the equivalence point for the titration of 60.7 mL of 0.574 M NH3 (Kh = 1.8 x 10-5) with 0.469 M HCI. (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation-examples include 1.23 and 120. and -123 and 123. and 12.3) A Moving to another question will save this response. Question 11 of 30

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 11 Calculate the pH at the equivalence point for the titration of 60.7 mL of 0.574 M NH3 (Kh = 1.8 x 10-5) with 0.469 M HCI. (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation--examples include 1.23 and 120. and -123 and 123. and 12.3) Question 11 of 30 A Moving to another question will save this response. ES esc F3 @ %23 % & 3. 4 6 7 8 9 P W E S D H ck C N command option ontion Gommand B
Transcribed Image Text:Question 11 Calculate the pH at the equivalence point for the titration of 60.7 mL of 0.574 M NH3 (Kh = 1.8 x 10-5) with 0.469 M HCI. (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation--examples include 1.23 and 120. and -123 and 123. and 12.3) Question 11 of 30 A Moving to another question will save this response. ES esc F3 @ %23 % & 3. 4 6 7 8 9 P W E S D H ck C N command option ontion Gommand B
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