Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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What can be said of two genes on the same chromosome, 49 map units apart?
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- Give correct typing answer with explanationarrow_forwardShow how breeding females of the vermilion/brown, cinnabar/brown, and scarlet/brown double mutants with males of the scarlet strain (instead of the cinnabar strain) would have also enabled us to differentiate between the three double mutant Drosophila strains. Include the genotypes of the breeding partners and the offspring, and the phenotypes of the offspring dont copy from any other site asap pleasearrow_forwardNext-generation sequencing reveals that six new mutations have occurred in the coding regions of genes in an individual diploid fly. If the coding regions of this fly comprise 100 million nucleotides per haploid genome, what is the mutation rate per nucleotide?arrow_forward
- In Meselson and Radding modified Holliday model, following branch migration, what are the possible number of heteroduplex regions that can occur? 3 4arrow_forwardYou are interested in studying position effect variegation in Drosophila using the chromosome depicted below: Deactivation of the w+ gene gives a white eye phenotype and deactivation of the rst+ gene gives a rough eye phenotype; the normal phenotypes are red and smooth. Because the rst+ and w+ genes have now been placed close to a heterochromatic domain, some sections (or sectors) of the eye display mutant phenotypes due to gene deactivation while others display the normal, wild type phenotype. Which phenotype would you not expect to see rst w Inverted X chromosome white smooth eye sectors white rough eye sectors red smooth eye sectors red rough eye sectorsarrow_forwardThe homologous chromosome pairs in our cells do not carry identical sequences in all loci. This heterozygosity (difference between the two.copies) can be altered in cancer: in fact, loss of heterozygosity at many loci is observed in cancer cells, through an increase in either homozygosity (two identical copies) or hemizygosity (i.e. loss of one copy). Researchers can take advantage of this loss of heterozygosity in cancer cells to identify genomic loci that contain cancer-critical genes. What type of gene would you expect to find in chromosomal regions with a loss of heterozygosity? Proto-oncogenes or tumour suppressor genes? Choose the correct answer here Proto-oncogenes Tumour Suppressor genesarrow_forward
- A group of scientists sequenced the genomes of 12 species of Drosophila (Drosophila 12 Genomes Consortium. 2007. Nature 450:203–218). Data on genome sizes and numbers of protein-encoding genes from this study are given in the accompanying table. Plot the number of protein-encoding genes as a function of genome size for the 12 species of Drosophila. Is there a relation between genome size and number of genes in fruit flies? How does this compare with the relation between genome size and number of genes across all eukaryotes?arrow_forwardExamine Figure . What type of chromosome (metacentric, submetacentric, acrocentric, or telocentric) is chromosome 1? What about chromosome 4?arrow_forwardWhat are the factor of expressed sequence tag?arrow_forward
- A line of mouse cells is grown for many generations in a medium with 15N. Cells in G1 are then switched to a new medium that contains 14N. Draw a pair of homologous chromosomes from these cells at the following stages, showing the two strands of DNA molecules found in the chromosomes. Use different colors to represent strands with 14N and 15N. Q. Cells in G1, before switching to medium with 14Narrow_forwardInternal Structures Function/significance Atrium (right & left) (plural – Atria) Bicuspid valve (AKA Mitral Valve) Chordae tendinae Endocardium Interventricular septum Myocardium Papillary muscle Semilunar valves (Aortic and Pulmonary) Trabeculae carnae Tricuspid valve Ventricle (right and left)arrow_forward6). To investigate the genetic control of locomotive behavior in the diploid nematode, Caenorhabditis elegans, eight "wiggly" mutants were isolated, which wiggle in an uncoordinated way rather than smoothly gliding. These eight mutants were crossed together in all possible pairwise combinations, yielding the results summarized in the table above (+ means that all the progeny were wild type, and m means that all the progeny showed the wiggly mutant phenotype). Organize the eight mutations into con lementation groups, each consisting of a group of mutations affecting the same gene. 1 2 3 4 5 6 7 8 1 E N+E 2 3+1 m + m 4 5 + m m E+ + + EE 6 ++E E+ +EE m m + + + + + + + + + m 7 8 ++4 ∞+E +E m m ++ Earrow_forward
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