Question #1 Study the following C program and answer the below questions Hint: you might run it in Dev C++ before starting answering the questions! #include int main(void){ int number; char choice; printf("Please enter an integer number: "); scanf("%d" , &number); printf"\nTo check whether the number is even or odd, press e \n"); printf"To check whether the number is positive or negative, press p n"): printf("To check whether the number is multiple of 10, press m \n"); printf"\nPlease enter your choice: "): scanf(" %c" , &choice); switch(choice) { case 'e': case 'E': if (number % 2 -- 0){ printf"n%d is even \n", number); else { printf"n%d is odd in", number): break; case 'p': case 'P': if (number > 0){ printf"n%d is positive \n", number): else if (number <0){ printf"n%d is negative \n", number); else printf"n%d is zero! n", number); break; case 'm': case 'M': if (number % 10- 0){ printf"n%d is a multiple of 10 \n" , number); else printf"n%d is NOT a multiple of 10 n" , number);: break; default: printf" NERROR: %c is unrecognized option!!! \n", choice); return 0; Page 2 of 8

Given C code: #include <stdio.h>typedef struct compound {  float realNumber;  float imaginaryNumber;} compound; compound add(compound n1, compound n2); int main() {  compound n1, n2, temp;   printf("For the first compound number \n");  printf("Enter the real and imaginary parts: ");  scanf("%f %f", &n1.realNumber, &n1.imaginaryNumber);   printf("\nFor the second compound number \n");  printf("Enter the real and imaginary parts: ");  scanf("%f %f", &n2.realNumber, &n2.imaginaryNumber);   temp = add(n1, n2);  printf("Sum = %.1f + %.1fi", temp.realNumber, temp.imaginaryNumber);   return 0;} compound add(compound n1, compound n2) {  compound temp;   temp.realNumber = n1.realNumber + n2.realNumber;  temp.imaginaryNumber = n1.imaginaryNumber + n2.imaginaryNumber;   return (temp);} Task: Please change the C program above to execute complicated numeral multiplication. Hint: (e+fi)(g+hi) = (eg−fh) + (eh+fg)i

#include using namespace std; int main() { int g; g = 0; while (g >= −6) { } Type the program's output } cout << g << endl; g = g - 4; return 0;

#include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; } Convert the product into pep9 assembly language.