Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Question 1: For a plane electromagnetic wave, the magnetic field at a point x and time t is B (x, t) = [1.2 × 10-7 sin (0.5 × 103 x + 1.5 × 1011 t) k] T. The instantaneous electric field E corresponding to B is: (speed of light c = 3 × 108 ms–1) 1) E (x, t) = [36 sin (1 × 103 x + 1.5 × 1011t) i] V / m 2) E (x, t) = [36 sin (0.5 × 103 x + 1.5 × 1011t) k] V / m 3) E (x, t) = [36 sin (1 × 103 x + 0.5 × 1011t) j] V / m 4) E (x, t) = [- 36 sin (0.5 × 103 x + 1.5 × 1011t) j] V / m

Question 1: For a plane electromagnetic wave, the magnetic field at a point x and time t is B (x, t) = [1.2 × 10-7 sin (0.5 × 103 x + 1.5 × 1011 t) k] T. The instantaneous electric field E corresponding to B is: (speed of light c = 3 × 108 ms–1) 1) E (x, t) = [36 sin (1 × 103 x + 1.5 × 1011t) i] V / m 2) E (x, t) = [36 sin (0.5 × 103 x + 1.5 × 1011t) k] V / m 3) E (x, t) = [36 sin (1 × 103 x + 0.5 × 1011t) j] V / m 4) E (x, t) = [- 36 sin (0.5 × 103 x + 1.5 × 1011t) j] V / m

icon
Related questions
Question

Question 1: For a plane electromagnetic wave, the magnetic field at a point x and time t is B (x, t) = [1.2 × 10-7 sin (0.5 × 103 x + 1.5 × 1011 t) k] T. The instantaneous electric field E corresponding to B is:

(speed of light c = 3 × 108 ms–1)

 

  1. 1) E (x, t) = [36 sin (1 × 103 x + 1.5 × 1011t) i] V / m
  2. 2) E (x, t) = [36 sin (0.5 × 103 x + 1.5 × 1011t) k] V / m
  3. 3) E (x, t) = [36 sin (1 × 103 x + 0.5 × 1011t) j] V / m
  4. 4) E (x, t) = [- 36 sin (0.5 × 103 x + 1.5 × 1011t) j] V / m
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer