Q5. Explain why when D is tangential to the surface, D.ds = O. * Because of the boundary condition between a dielectric surface to charged surface has no tangential component Because Gauss's law is an alternative formulation to obtain electric flux density and electric field intensity by the relation with electric charge Because of Divergence theorem and Stoke theorem prove so Because when D only has normal component for charge surface

Consider a conductor plate carrying a current I as shown in the figure. Current flows in the negative direction. It is also known that a conductor has a charge-carrying density of n with 1 particle carrying a charge q . This conductor plate is then placed on the a region with an external magnetic B field in the z direction . Determine the potential difference across the conductors! State the answer in terms of B, n, q, I, B, and d! (Assume positive charge carrier) *This potential, which is often referred to as the Hall potential V_H, is commonly measured in experiments to determine the properties of a material. However, there are other quantities that are also measured namely the Hall coefficient R_H. In ordinary metals, the relationship between R_H and V_H is as following (equation in figure)

Two infinitely long, parallel lines of charge with linear charge densities 9.0 µC/m and −9.0 µC/m are separated by a distance of 0.50 m. What is the net electric field at point C as shown in the figure below? (Express your answers in vector form.)