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c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to e) You should have found that the charges on th determine the unknown charges Q1 and Q2. order to find Qu. d) What are the charges on the inner surfaces the slabs? inner surfaces of the slabs are equal an opposite. This will be true regardless of hov much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qu and Q2 as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Qi.

c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to e) You should have found that the charges on th determine the unknown charges Q1 and Q2. order to find Qu. d) What are the charges on the inner surfaces the slabs? inner surfaces of the slabs are equal an opposite. This will be true regardless of hov much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qu and Q2 as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Qi.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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please answer d and e

1. A pair of thick conducting slabs are fixed in place near one other as shown, with their faces parallel. The faces have area A, which we will take to be very large compared to the slabs' separation. Initially the slabs are neutral, but then a net charge of +5 C is placed on the left slab, and a net charge of +3 C is placed on the right slab. When things have settled down, some amount of charge has migrated to the outer faces of the slabs, and some amount of charge has migrated to the inner faces of the slabs. This situation is diagrammed below. +5C +3 C +5C +3C 5-Q, 3-Q
Transcribed Image Text:1. A pair of thick conducting slabs are fixed in place near one other as shown, with their faces parallel. The faces have area A, which we will take to be very large compared to the slabs' separation. Initially the slabs are neutral, but then a net charge of +5 C is placed on the left slab, and a net charge of +3 C is placed on the right slab. When things have settled down, some amount of charge has migrated to the outer faces of the slabs, and some amount of charge has migrated to the inner faces of the slabs. This situation is diagrammed below. +5C +3 C +5C +3C 5-Q, 3-Q
Notice that the charges on the loft slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to determine the unknown charges Qi and Qa. c) Repeat parts (a) and (b) for the right slab, i order to find Qu. d) What are the charges on the inner surfaces the slabs? e) You should have found that the charges on th. inner surfaces of the slabs are equal an opposite. This will be true regardless of how much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qi and Qa as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Q.
Transcribed Image Text:Notice that the charges on the loft slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to determine the unknown charges Qi and Qa. c) Repeat parts (a) and (b) for the right slab, i order to find Qu. d) What are the charges on the inner surfaces the slabs? e) You should have found that the charges on th. inner surfaces of the slabs are equal an opposite. This will be true regardless of how much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qi and Qa as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Q.
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