c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to e) You should have found that the charges on th determine the unknown charges Q1 and Q2. order to find Qu. d) What are the charges on the inner surfaces the slabs? inner surfaces of the slabs are equal an opposite. This will be true regardless of hov much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qu and Q2 as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Qi.
c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to e) You should have found that the charges on th determine the unknown charges Q1 and Q2. order to find Qu. d) What are the charges on the inner surfaces the slabs? inner surfaces of the slabs are equal an opposite. This will be true regardless of hov much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qu and Q2 as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Qi.
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter1: Atomic Structure
Section: Chapter Questions
Problem 6RQ: How many valence electrons are generally contained in materials used for insulators?
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Question
please answer d and e
Transcribed Image Text:1. A pair of thick conducting slabs are fixed in
place near one other as shown, with their
faces parallel. The faces have area A, which
we will take to be very large compared to the
slabs' separation.
Initially the slabs are neutral, but then a net
charge of +5 C is placed on the left slab, and a
net charge of +3 C is placed on the right slab.
When things have settled down, some amount
of charge has migrated to the outer faces of
the slabs, and some amount of charge has
migrated to the inner faces of the slabs. This
situation is diagrammed below.
+5C
+3 C
+5C
+3C
5-Q, 3-Q
Transcribed Image Text:Notice that the charges on the loft slab add up
to +5 C as required by charge conservation-
and likewise for the right slab. Notice also
that, in accordance with the rules for
conductors, all charges reside on the surfaces
of the conductors. The goal of this question
will be to use other rules for conductors to
determine the unknown charges Qi and Qa.
c) Repeat parts (a) and (b) for the right slab, i
order to find Qu.
d) What are the charges on the inner surfaces
the slabs?
e) You should have found that the charges on th.
inner surfaces of the slabs are equal an
opposite. This will be true regardless of how
much charge is on either slab. Can you prov
this by drawing an appropriate Gaussia
surface and making use of the fact that th
field in either slab vanishes? •
a) Treating Qi and Qa as known quantities, use
superposition to find an expression for the
electric field within the left slab.
b) Taking into account the fact that the slab is a
conductor, use this expression to find Q.
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