c) Repeat parts (a) and (b) for the right slab, i- Notice that the charges on the left slab add up to +5 C as required by charge conservation- and likewise for the right slab. Notice also that, in accordance with the rules for conductors, all charges reside on the surfaces of the conductors. The goal of this question will be to use other rules for conductors to e) You should have found that the charges on th determine the unknown charges Q1 and Q2. order to find Qu. d) What are the charges on the inner surfaces the slabs? inner surfaces of the slabs are equal an opposite. This will be true regardless of hov much charge is on either slab. Can you prov this by drawing an appropriate Gaussia surface and making use of the fact that th field in either slab vanishes? • a) Treating Qu and Q2 as known quantities, use superposition to find an expression for the electric field within the left slab. b) Taking into account the fact that the slab is a conductor, use this expression to find Qi.

Three-segment transformers are a type of transformer used to transform voltages of electrical systems into three ranges. Two type transformers are shell-type transformer and core type transformer. In brief, it could be described because of the exquisite …

Ever since electricity has been created, people have started using it in its entirety. We see many types of Transformers in the neighborhoods. Some are smaller in size and some are very large. They are used according to their requirements. Many of us hav…