Q5 A road at a constant RL of 180.00 runs North to South. The ground East to West is level. The surface levels along the centre line of the road are as follows: Chainage in meter: 0 30 60 90 120 150 180 Level in meter: 183.50 182.45 182.15 181.55 180.95 182.05 180.80 Compute the volume of cutting, given that the width at formation level is 8 m and the side slopes 1 to 1. The centre depths of the cutting at 30 m intervals may be determined by subtracting the formation from the respective ground levels.

Q5 A road at a constant RL of 180.00 runs North to South. The ground East to West is level. The surface levels along the centre line of the road are as follows: Chainage in meter: 0 30 60 90 120 150 180 Level in meter: 183.50 182.45 182.15 181.55 180.95 182.05 180.80 Compute the volume of cutting, given that the width at formation level is 8 m and the side slopes 1 to 1. The centre depths of the cutting at 30 m intervals may be determined by subtracting the formation from the respective ground levels.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QS) A road at a constant R.L of 180.00m runs North to South. The ground East to West is level. The surface levels along the center line of the road are as follows: Changing in meter: 0 30 60 90 120 150 180 Level in meter: 183.50, 182.45, 182.15, 181.55, 180.95, 182.05, 180.80 Compute the volume of cutting by both the trapezoidal and prismoidal formulas, given that the width at formation level is 8m and the side slopes is 1 to 1.
: Workout the Earthwork quantities in embankment and cutting for the chainage length of 600 meters. Formation width is 20m. Side slopes in embankment is 2:1 and in cutting is 1.5:1. There is no transverse slope. Rising gradient of 1:250 upto 250m chaniage. Rising gradient of 1:100 upto 600m chainage. Chainage 0 50 100 150 200 250 300 350 R.L of Ground 152.0 152.35 152.6 152.8 153.0 152.6 152.2 151.5 R.L of Formation 151.6 Chainage 400 450 500 550 600 R.L of Ground 151.2 150.5 150.3 150.5 150.7 R.L of Formation 155.4
A trapezoidal channel has a side slope of 2, a bottom width of b meters and a depth of flow of y meters. What is the wetted perimeter of the channel? O a. O b. by + O d. 260.5 y + 26⁰.5 Ọ C. b +2yb25 by + 2y60.5
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