Q4) Select the correct answer, Note Solve and select if it is required. A 95% confidence interval for population proportion p is 32.4% to 47.6%, the value of sample proportion is: I- (a) 40% (b) 32.4% (c) 47.6% (d) 80% II- A 95% confidence interval for the mean of a population is such that: (a) It contains 95% of the values in the population

Virginia wants to estimate the percentage of students who live more than three miles from the school. She wants to create a 95% confidence interval which has a margin of error of at most 5%. How many students should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above.

Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval. n = 36, x = 64.4 seconds, s = 6.5 seconds. The margin of error is seconds. (Round to one decimal place as needed.) an example 4

A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our…

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

A new fertilizer was applied to the soil of 239 bean plants. 11% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval:

Determine the margin of error for the confidence interval for the mean: 23 +1.7 The margin of error is

Which confidence interval would lead you to Fail to Reject H0? Group of answer choices Test value: 10 Confidence Interval: 13.1 – 15.1 Test value: 5 Confidence Interval: 5.6 – 6.9 Test value: 5 Confidence Interval: 4.5 – 6.3 Test value: 10 Confidence Interval: 9.2 – 9.8

If n = 580 and X = 464, construct a 90% confidence interval for the population proportion, p.Give your answers to three decimals______< p < ______

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96