Q4- Answer the following1- Classification of plastic deformation2- What is the difference between the thin sheet and plate?3- What is the difference between engineering stress and true stressin a tensile test ?4- A round sheet metal slug produced in a hole punching operation will havethe same diameter as which of the following? (a) die opening, or (b) punch.5- proof ( ɛl+ £2+ £3=0) at constant volume6- List three of the products produced on a rolling mill.7- Identify the three basic types of sheet metal working operations.8- Which of the following is typical of the work geometry in sheet metalprocesses? (a) high volume-to-area ratio, or (b) low volume-to-area ratio

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Q4- Answer the following 1- Classification of plastic deformation 2- What is the difference between the thin sheet and plate? 3- What is the difference between engineering stress and true stress in a tensile test ?

Q4- Answer the following 1- Classification of plastic deformation 2- What is the difference between the thin sheet and plate? 3- What is the difference between engineering stress and true stress in a tensile test ?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In tensile test a plain carbon steel specimen has a (40mm) gauge length and the Final area (A final) of specimen after tensile test was 264.327. The load which caused fracture was (122.5 KN). After fracture, the final length was 47.516mm Choose the correct answers for the following sentences: Initial area (A final) of specimen * O568.254 O 313.994 325.256 152.368
What are the different types of Indenters used in Rockwell Hardness Testing?
please I just need the answer for :Final Diameter of the Specimen after Fracture, just this quastion only.
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 147 kN. - Length of the specimen is 28 mm. - The yield strength is 75 kN/mm2. - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 16 kN, iv) Young's Modulus if the elongation is 1 mm at 16 kN and (v) Final diameter if the percentage of reduction in area is 22 Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm) Initial Cross-sectional Area (in mm2)
Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1E: Of those two materials (F75 CoCr alloy (as cast) and F90 CoCr alloy (hot forged)), which materials would you select to assure that the deformation is entirely elastic (No yield!)?
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 151 kN. - Length of the specimen is 23 mm. - The yield strength is 79 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 17 kN, iv) Young's Modulus if the elongation is 2.4 mm at 17 kN and (v) Final diameter if the percentage of reduction in area is 24 %. THE QUESTION IS : FIND THE Final Diameter of the Specimen after Fracture (in mm)????
In a tensile test for an aluminum alloy, the sample is 2 inches long and 0.5 inches in diameter. The proportional portion of the tension stress-strain diagram for an aluminum alloy is shown below. It the diameter change of the sample was also monitored during the above test, and it was found that the lateral strain of the sample is 1/3 of its axial longitudinal strain, what is the Poisson' ratio of the material under test: ___. Calculate your answer to 2 decimal place.
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 157 kN. - Length of the specimen is 23 mm. - The yield strength is 89 kN/mm2. - The percentage of elongation is 45 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 18 kN, iv) Young's Modulus if the elongation is 1.3 mm at 18 kN and (v) Final diameter if the percentage of reduction in area is 25 %. Solution: Initial Cross-sectional Area (in mm2) The Diameter of the Specimen (in mm) Final Length of the Specimen (in mm) Stress at the elastic load (in N/mm2) Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)
In tensile test a plain carbon steel specimen has a (40mm) gauge length and the Final area (A final) of specimen after tensile test was 264.327. The load which caused fracture was (122.5 KN). After fracture, the final length was 47.516mm The % reduction in area is * O 15.819% 18.819 O 17.819 O 20.819
1. Ductile materials are tougher than brittle ones II. Tensile tests are not used when the material is brittle III. Brittle materials reach much higher ultimate stresses in tension than in compression Which statement(s) given above is/are true?
Based upon the information in the table below, which material is the stiffest? Elastic Strain at Fracture Fracture Yield Strength (MPa) Tensile Modulus Strength (MPa) 120 550 340 Fractures before yielding 850 Strength (MPa) 105 500 265 650 720 Material 100 415 310 0.40 0.15 0.23 (GPa) 150 310 210 350 210 700 0.14 OE OB A. OD
Answer Part b