Q4: A steel cantilever, the factor of safety is 2, the sensitivity factor 0.9, surface finish factor is 0.81, size factor is 0.8, Sut= 600 MPa and yield strength is 310 MPa .Calculate the diameter at the fillet. Neglect the transverse shear stress. 0.2d d 11-14 -50 kN 150kN 1 100mm + 200mm

Problem 4 Press-Fit (3-116) Matlab Code is for (3-117) The table gives data concerning the shrink fit of two cylinders of differing materials and dimensional specification in inches. Elastic constants for different materials may be found in Table A-5. Identify the radial interference &, then find the interference pressure p, and the tangential normal stress on both sides of the fit surface. If dimensional tolerances are given at fit surfaces, repeat the problem for the highest and lowest stress levels. Problem Number Material 3-116 3-117 Inner Cylinder di Steel Steel 0 0 do 2.002 2.002 Outer Cylinder D; Material Steel Cast iron 2.000 2.000 Do 3.00 3.00

2. At a machined shaft shoulder the small diameter d is 25mm the large diameter D is 40mm, and the fillet radius is 2.5 The bending moment is 2300N mm and the steady torsion moment is 1800 N mm The heat-treated steel shaft has an ultimate strength of Sut- 850Mpa The reliability goal is 099 (ka- 0.786, kb 0.870, ke 0.814) Determine the fatigue factor of safety of the design described in this section

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In the diagram below shows a circula bar , made of AISI 1040 OQT 1300 steel (SU = 600 MPa), is loaded with an axial tensile loading P. Find the modified endurance strength (SE) and the modified fatigue strength (SF) for the bar if D = 36 mm, d = 30 mm, and r = 2.4 mm. Use the number of cycles tofracture to be 5 × 105. Assume that the surface finish factor, kf, is 0.85, the size factor, kS, is 0.85, and the notch sensitivity factor, qn, is 0.75. Use the following equations if needed,

MECH.ENG. DESIGN 1 PART 2

Q8

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The shaft material is AISI 1040CD steel. The reliability of the design is 90%. The r/d for the shoulder is 0.02. If the design is not feasible, give reasons and suggest modifications. You do not have to consider any other failure criterion. You may assume that the torque is steady and the bending moment is fully reversed.