
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Num1<<=3;
Int num1 = num2+30%3B
Q2 Write assembly code equivalent to the following C code
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- Translate the following C++ program to Pep/9 assembly language. Code should also be commented. #include <iostream>using namespace std;int num1;int num2;int main (){ int i; cout << "Enter two integers; cin >> num1 >> num2; for (i = num1; i <= num2; i++) cout << i << endl; return 0;}arrow_forwardisincreasing function write an hla assembly language program that implements the following function: procedure isincreasing( i: uns32; j : uns32; k : uns32 ); @nodisplay; @noframe; this function should return into eax the value 1 if i < j and j < k; otherwise, return into eax the value 0. in order to receive full credit, you should be preventing register corruption by preserving and then restoring the value of any register your function touches. this rule applies to every register except for eax which is being used to pass an answer back to the calling code. feed me i: 5 feed me j: 13 feed me k: 33 eax = 1arrow_forwardTranslate the following C++ program into assembly language: #include <iostream> using namespace std; int main() { char letter; int countA = 0, countB = 0, countC = 0; cin >> letter; do { switch (letter) { case 'A' : countA++; break; case 'B' : countB++; break; case 'C' : countC++; break; } cin >> letter; } while (letter != 'X'); cout << "Number of A's " << countA << endl << "Number of B's " << countB << endl << "Number of C's " << countC << endl; return 0; } Use local variables (except for messages, of course) and the branch indexed for the switch statement.arrow_forward
- Convert the following c++ code into pep9 assembly language #include <iostream> using namespace std; int times(int mpr, int mcand) { int prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } return prod; } int main(){ int n, m; cout << "Enter two numbers: "; cin >> n >> m; cout << "Product: " << times(n, m) << endl; return 0; } Submit: pep source code and as well as the screenshot of pep9 assembly code running in the pep stimulator.arrow_forwardConvert the following c++ code into pep9 assembly language. #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }arrow_forwardConvert the following C++ programs into Pep/9 assembly #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; } Submit: Pep/9 source code along with screen capture showing it running in the Pep simulatorarrow_forward
- IN THE C PROGRAMMING LANGUAGE j = 15; k = 9 // what are the values for n,m,and p after these operations: --j ; k++ ; n = j - ++k; m = j-- + k--; p = k + j;arrow_forwardWhat design flaws do these factors possess? Most programming languages permit just one kind of variable per pointer.arrow_forwardConvert the following c++ code into pep9 assembly language. #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }arrow_forward
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