#include using namespace std; const numLoops = 10; int main(){   int x = 0;    do {       cout << x << endl;      ++x;   } while (x < numLoops);   return 0; }

Complete the following C++ programs into Pep/9 assembly language: 1) int main(){int cop;    int driver;    cop = 0;    driver = 40;    while (cop <= driver) {        cop += 25;        driver += 20;    }    cout << cop;    return 0;}

Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…

Translate the following C++ program to Pep/9 assembly language. Code should also be commented. #include <iostream>using namespace std;int Lesser(int x, int y) {    int least;    if (x < y)        least = x;    else        least = y;    return least;}int main(){    int num1;    int num2;    cout << "Enter two integers: ";    cin >> num1 >> num2    cout << "Lesser: "         << Lesser(num1, num2);         << endl;    return 0;}

translate a c++ program into pep/9 assembly language #include <iostream> using namespace std; int myAge;void ShowVal(int age){ cout << "Age:" << age << endl;} int main() {cout << "Enter age: ";cin >> myAge;ShowVal(myAge);return 0;}

Convert the following C++ programs into Pep/9 assembly #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; } Submit: Pep/9 source code along with screen capture showing it running in the Pep simulator

Convert the following C++ program to pep9/Assembly language BR Main format not machine language #include <iostream>using namespace std; int times(int mpr, int mcand){int prod = 0;while (mpr != 0){if (mpr % 2 == 1)prod = prod + mcand;mpr /= 2;mcand *= 2;} return prod;} int main(){ int n, m; cout << "Enter two numbers: ";cin >> n >> m; cout << "Product: " << times(n, m) << endl; return 0;}

Write the report of this course that is the explanation of the algorithm in this program #include<iostream> // include necessary libraries #include<stack> // include necessary libraries #include<locale> // include necessary libraries #include <climits> // include necessary libraries using namespace std; int preced(char ch) {   // defining precedence function if(ch == '+' || ch == '-') {  // if condition return 1;}else if(ch == '*' || ch == '/') {return 2;}else {return 0;}} string inToPost(string infix ) {  // defining push function  stack<char> stk;stk.push('#');   string postfix = "";   string::iterator it; for(it = infix.begin(); it!=infix.end(); it++) { // for loop if(isalnum(char(*it)))  // if condition postfix += *it;else if(*it == '(') // if condition stk.push('(');else if(*it == ')') { // if condition while(stk.top() != '#' && stk.top() != '(') {postfix += stk.top();  stk.pop(); // pop element }stk.pop();   }else {if(preced(*it) >…

Please help c++language

15. Translate the following C program to Pep/9 assembly language. #include int main() { int numitms, j, data, sum; scanf("%d", &numItms); sum = 0; for (j = 1; j <= numitms; j++) { scanf("%d", &data); sum += data; } printf ("Sum: %d\n", sum); return 0; } Sample Input 48-376 Sample Output Sum: 18