Q2: The following stress and strain values were measured in the plastic region during a tensile test carried out on a new experimental metal: (1) true stress = 43.608 lb/in2 and true strain = 0.27. (2) true stress Based on these data points, determine the (strength coefficient and strain- hardening exponent. Find the engineering stress and strain at the second noint 52.048 lb/in2 and true strain = 0.85. %3D

For some metal alloy, a true stress 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 418 MPa (60630 psi) is applied if the original length is 500 mm (19.69in) ? Assume a value of 0.22 for the strain- hardening exponent, n

3 please include sketch

6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture)