Q2: Full journal bearing of 50 mm diameter and 100 mm long has a bearing pressure of 1.4 N/mm'. The speed of the journal is 900 r.p.m. and the ratio of journal diameter to the diametral clearance is 1000. The bearing is lubricated with oil whose absolute viscosity at the operating temperature of 75°C may be taken as 0.011 kg/m-s. The room temperature is 35°C. where (C 280 W/m /° C) Find:, 1-The amount of artificial cooling required. 2- The mass of the lubricating oil required, if the difference between the outlet and inlet temperature of the oil is 10°C. Take specific heat of the oil as 1850 J/ kg / °C. W= p * d.l, Qt = m.S.t. Qg =µ W.V, (t-ta) =;(t, - ta) %3D 33 ndN Qa = C. I. d(t, - la). H= +k, Amount of artificial cooling required = Q, - Qd. V = 60 108 (P

Elements Of Electromagnetics
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Q2: Full journal bearing of 50 mm diameter and 100 mm long has a bearing pressure of 1.4 N/mm'. The speed of the
journal is 900 r.p.m. and the ratio of journal diameter to the diametral clearance is 1000. The bearing is lubricated with
oil whose absolute viscosity at the operating temperature of 75°C may be taken as 0.011 kg/m-s. The room
temperature is 35°C. where (C = 280 W/m 1° C) Find:,1-The amount of artificial cooling required. 2- The mass of
the lubricating oil required, if the difference between the outlet and inlet temperature of the oil is 10°C. Take specific
heat of the oil as 1850 J/ kg / °C.
W= p* d.l, Qt = m.S.t. Qg = u W.V, (t-ta) =;(t,-ta)
33
ndN
Qa = C. I. d(t, - la). H =
+k, Amount of artificial cooling required = Q, - Qa. V =
60
108 (P
Transcribed Image Text:Q2: Full journal bearing of 50 mm diameter and 100 mm long has a bearing pressure of 1.4 N/mm'. The speed of the journal is 900 r.p.m. and the ratio of journal diameter to the diametral clearance is 1000. The bearing is lubricated with oil whose absolute viscosity at the operating temperature of 75°C may be taken as 0.011 kg/m-s. The room temperature is 35°C. where (C = 280 W/m 1° C) Find:,1-The amount of artificial cooling required. 2- The mass of the lubricating oil required, if the difference between the outlet and inlet temperature of the oil is 10°C. Take specific heat of the oil as 1850 J/ kg / °C. W= p* d.l, Qt = m.S.t. Qg = u W.V, (t-ta) =;(t,-ta) 33 ndN Qa = C. I. d(t, - la). H = +k, Amount of artificial cooling required = Q, - Qa. V = 60 108 (P
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