Q1.Calculate the molarity of CH3COOH (in mol dm-3) in the sample vinegar Q2.Calculate the concentration of CH3COOH (in g dm-3) in the sample vinegar Q3. Write the equation of the neutralization reaction in this experiment

Determine the Concentration of Ethanoic Acid in Vinegar 

Equipment / Apparatus: 

 250-mL conical flasks 

 Clamp 

 Burette 

 Graduated cylinder 

 Pipette 

Reagents / Materials: 

 Vinegar 

 Phenolphthalein indicator 

 0.2 M NaOH (standardized) 

Calculation: Molarity (M) of ethanoic acid 

 The average measured volume of the NaOH from titration: 

Average volume of NaOH used = (21.5ml + 21.5ml + 21.6ml) / 3 =21.5ml

 No of mole of NaOH = Concentration of NaOH (0.2M) × Average volume of NaOH used 

When an acid is completely neutralized: No of moles of CH3COOH = No of moles of NaOH 

 Using the moles of CH3COOH, the molarity of ethanoic acid in the 5.0-mL sample of vinegar is calculated: 

Molarity (M) CH3COOH = moles CH3COOH / volume of vinegar (0.005 dm3). 

Calculation: Mass / Volume Percent (m/v) of ethanoic acid 

To calculate the percent (m/v) of CH3COOH in vinegar, we convert the moles of ethanoic acid to grams using the molar mass of ethanoic acid, 60.1 g/mole. 

Mass of CH3COOH = no of moles of CH3COOH × 60.1 

Mass / volume percent (m/v) = mass of CH3COOH / volume of vinegar (0.005 dm3) 

(Above is sources)

Q1.Calculate the molarity of CH3COOH (in mol dm-3) in the sample vinegar

Q2.Calculate the concentration of CH3COOH (in g dm-3) in the sample vinegar

Q3. Write the equation of the neutralization reaction in this experiment