PXV=RXT where v=specificvolume R= idealgasconstantfwater-461.5 J/kg.K Therefore V=- RXT P 461.5×623 V= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteantable At P=15MPaandT=350°C,usingsteamtable thespecificvolumeis, v=0.01148 m³/kg Theerrorinthespecificvolumeforthefirsttwocase: Case (a) Theerrorinthespecificvolumeis, V-V a C %Error= x100 V C where v=thespecificvolume incase (a) v=thespecificvolume incase (c) 0.01917-0.01148 %Error= x100 0.01148 % Error= 67%

Elements Of Electromagnetics
7th Edition
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Author:Sadiku, Matthew N. O.
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I am not able to find the values for part (b) and (c) So please upload image of the chart and table.
PXV=RXT
where v=specificvolume
R= idealgasconstantfwater=461.5 J/kg.K
Therefore
RXT
V=
P
461.5×623
v=
15×106
v=0.01917 m³/kg
(b) Usingthgeneralized bmpressibilityhart
At P=15MPaandT=350°C, usingompressiblityl
thespecificvolumeis,
v=0.01246 m³/kg
(c) Usingthesteantable
At P=15MPaandT=350°C, using steamtable
thespecificvolumeis,
v=0.01148 m³/kg
Theerrorinthespecificvolumeforthefirsttwocase:
Case (a) Theerrorinthespecific volumeis,
Va-Ve
а
%Error=
×100
where v=thespecific volume incase (a)
v=thespecificvolumeincase (c)
0.01917-0.01148
%Error=
×100
0.01148
% Error=67%
Transcribed Image Text:PXV=RXT where v=specificvolume R= idealgasconstantfwater=461.5 J/kg.K Therefore RXT V= P 461.5×623 v= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteantable At P=15MPaandT=350°C, using steamtable thespecificvolumeis, v=0.01148 m³/kg Theerrorinthespecificvolumeforthefirsttwocase: Case (a) Theerrorinthespecific volumeis, Va-Ve а %Error= ×100 where v=thespecific volume incase (a) v=thespecificvolumeincase (c) 0.01917-0.01148 %Error= ×100 0.01148 % Error=67%
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