public static int think(int x) { if(x<10) if(x%2!=0) return x; else return 0; else if(x%2!=0) return x%10 + think (x/10); else return think(x/10); } Trace (in details) the calling of the above method with any input from your choice returned value will be 19.

Consider the following method: public static void method (int x, int y) { if (x < y) { method (x+1, y); System.out.print (x + " "); } } What will happen as the result of calling method (2,6)? (Select all correct answers) output will be 6 5 4 3 2 Program goes to an infinite loop because of errors in recursive calls 5 recursive calls will be made from method (3,6) to method (7,6) output will be 5 4 3 2 method (6, 6) will be called inside of the recursion 4 recursive calls will be made from method (3,6) to method (6,6) method (5, 6) will be called inside of the recursion

49, question is in java, thanks

When looking at this code making recursive calls, how would I identify how many recursive calls are being made?

Consider the following recursive method:   Public static int Fib(int a1, int a2, int n){   if(n == 1)      return a1;   else if (n == 2)      return a2;else      return Fib(a1, a2, n-1) + Fib(a1, a2, n-2);} Please draw the recursion trace for Fib(2,3,5)

Given a list of integers, you want to know whether it is possible to divide the integers into two sets, so that the sums of the two sets are the same. Every integer must be in one set or the other. Write a recursive helper method that takes any number of arguments you like, and make the initial call to your recursive helper method from equalSum(). Do not use any loops or regular expressions. Test case 1: equalSum([2, 3, 5]) true Test case 2: equalSum([2, 2, 5]) false

Note that you can only use recursion to solve Q1  and you cannot use any loop. You are free to add helper methods, but you are not allowed to change the method header.Question 1: Crazy seriesIn this session, you need to implement the crazy series method. In the crazy series, you will be given a starting number. Then, you need to times 2 for each number until the number is greater than 100. After the number is greater than 100, you need to divide 3 until we reach the number is less than 5. Note that the input number must be greater than 0, and you are not allowed to use loop here.For example,crazySeries(10) should return ArrayList [10.0, 20.0, 40.0, 80.0, 160.0, 53.333333333333336, 17.77777777777778, 5.9259259259259265, 1.9753086419753088]crazySeries(5) should return ArrayList [5.0, 10.0, 20.0, 40.0, 80.0, 160.0, 53.333333333333336, 17.77777777777778, 5.9259259259259265, 1.9753086419753088]crazySeries(1) should return ArrayList [1.0, 2.0, 4.0, 8.0, 16.0, 32.0, 64.0, 128.0,…

change Summation Integers problem to Finding the minimumproblem. Make sure you properly wrote/updated all text messages, method names,and math calculations.Hint: You can use java.lang.Math.min() method.Example: System.out.printf("The min of the integers %4d and %4d and %4dis %7d\n", a, b, c,d MinTest(a, b, c,d)); fix below code structure

I have two questions: Is my programs code the most effective way at finding recursion or is there a much better and cleaner way? Why is the program showing 0 when I implement a number that depth is greater than 100? Shouldn't it show the number 1?   Source code: package recursiveModule; public class RecursiveMethod {    public static long calculateFactorial(int n, int depth) {        if (depth > 100 || n <= 1) {            return 1;        }                return n * calculateFactorial(n - 1, depth + 1);    }          public static void main(String[] args) {                             System.out.println("Factorial of 1 is " + RecursiveMethod.calculateFactorial(1, 0));                System.out.println("Factorial of 8 is " + RecursiveMethod.calculateFactorial(8, 0));                                      System.out.println("Factorial of 101 is " + RecursiveMethod.calculateFactorial(101, 0));                                   } }