Provide a curved arrow mechanism for the following reaction. NaCl CI

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Curved Arrow Mechanism for the Reaction**

In this reaction, you are asked to provide a curved arrow mechanism for the given chemical transformation. The reactant is a compound with an iodine (I) atom, and it reacts with sodium chloride (NaCl) to produce a compound where chlorine (Cl) is substituted in place of iodine.

### Reaction Steps:

1. **Reactant Description**: The starting material is an organic compound with an iodide group attached to a carbon atom. The structure shows three carbon branches.

2. **Reaction Process**: 
   - The iodide ion (I-) will leave, forming a carbocation intermediate. 
   - The chloride ion (Cl-) from NaCl will then attack the carbocation, replacing the iodine with chlorine.

3. **Product Description**: The final product is similar to the original compound, except the iodine atom has been replaced by a chlorine atom.

### Explanation:

- **Curved Arrows**: Use curved arrows to show the movement of electrons. 
  - One arrow should depict the departure of the iodine atom, indicating the formation of the carbocation.
  - Another arrow should show the attack of the chloride ion on the carbocation, leading to the substitution.

This kind of reaction illustrates a typical nucleophilic substitution process in organic chemistry, specifically an SN1 mechanism, where the leaving group departs before the nucleophile attacks.
Transcribed Image Text:**Curved Arrow Mechanism for the Reaction** In this reaction, you are asked to provide a curved arrow mechanism for the given chemical transformation. The reactant is a compound with an iodine (I) atom, and it reacts with sodium chloride (NaCl) to produce a compound where chlorine (Cl) is substituted in place of iodine. ### Reaction Steps: 1. **Reactant Description**: The starting material is an organic compound with an iodide group attached to a carbon atom. The structure shows three carbon branches. 2. **Reaction Process**: - The iodide ion (I-) will leave, forming a carbocation intermediate. - The chloride ion (Cl-) from NaCl will then attack the carbocation, replacing the iodine with chlorine. 3. **Product Description**: The final product is similar to the original compound, except the iodine atom has been replaced by a chlorine atom. ### Explanation: - **Curved Arrows**: Use curved arrows to show the movement of electrons. - One arrow should depict the departure of the iodine atom, indicating the formation of the carbocation. - Another arrow should show the attack of the chloride ion on the carbocation, leading to the substitution. This kind of reaction illustrates a typical nucleophilic substitution process in organic chemistry, specifically an SN1 mechanism, where the leaving group departs before the nucleophile attacks.
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