**Curved Arrow Mechanism for the Reaction**In this reaction, you are asked to provide a curved arrow mechanism for the given chemical transformation. The reactant is a compound with an iodine (I) atom, and it reacts with sodium chloride (NaCl) to produce a compound where chlorine (Cl) is substituted in place of iodine.### Reaction Steps:1. **Reactant Description**: The starting material is an organic compound with an iodide group attached to a carbon atom. The structure shows three carbon branches.2. **Reaction Process**: - The iodide ion (I-) will leave, forming a carbocation intermediate. - The chloride ion (Cl-) from NaCl will then attack the carbocation, replacing the iodine with chlorine.3. **Product Description**: The final product is similar to the original compound, except the iodine atom has been replaced by a chlorine atom.### Explanation:- **Curved Arrows**: Use curved arrows to show the movement of electrons. - One arrow should depict the departure of the iodine atom, indicating the formation of the carbocation. - Another arrow should show the attack of the chloride ion on the carbocation, leading to the substitution.This kind of reaction illustrates a typical nucleophilic substitution process in organic chemistry, specifically an SN1 mechanism, where the leaving group departs before the nucleophile attacks.

Nucleophilic substitution reaction is an organic reaction in which a nucleophile replaces another…

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Provide a curved arrow mechanism for the following reaction. NaCl CI

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Curved Arrow Mechanism for the Reaction**

In this reaction, you are asked to provide a curved arrow mechanism for the given chemical transformation. The reactant is a compound with an iodine (I) atom, and it reacts with sodium chloride (NaCl) to produce a compound where chlorine (Cl) is substituted in place of iodine.

### Reaction Steps:

1. **Reactant Description**: The starting material is an organic compound with an iodide group attached to a carbon atom. The structure shows three carbon branches.

2. **Reaction Process**:
- The iodide ion (I-) will leave, forming a carbocation intermediate.
- The chloride ion (Cl-) from NaCl will then attack the carbocation, replacing the iodine with chlorine.

3. **Product Description**: The final product is similar to the original compound, except the iodine atom has been replaced by a chlorine atom.

### Explanation:

- **Curved Arrows**: Use curved arrows to show the movement of electrons.
- One arrow should depict the departure of the iodine atom, indicating the formation of the carbocation.
- Another arrow should show the attack of the chloride ion on the carbocation, leading to the substitution.

This kind of reaction illustrates a typical nucleophilic substitution process in organic chemistry, specifically an SN1 mechanism, where the leaving group departs before the nucleophile attacks.

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