Prolog. R emember the "take" function of Haskell? It can be defined in Haskell as: take :: Int -> [a] -> [a] take 0 _ = [] take _ [] = [] take n (x:xs) = x : take (n-1) xs Formulate the appropriate Prolog predicate "take(N,Xs,Ys)" which is true if (and only if) "Ys" is what results from taking "N" elements from "Xs". That is, "take(3,[1,2,3,4,5],[1,2,3])." would evaluate to "true", or "take(3,[1,2,3,4,5],Ys)." would give "Ys = [1,2,3]", while "take(3,[1,2],Ys)" would give "Ys = [1,2]"

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Prolog. R emember the "take" function of Haskell? It can be defined in Haskell as: take :: Int -> [a] -> [a] take 0 _ = [] take _ [] = [] take n (x:xs) = x : take (n-1) xs Formulate the appropriate Prolog predicate "take(N,Xs,Ys)" which is true if (and only if) "Ys" is what results from taking "N" elements from "Xs". That is, "take(3,[1,2,3,4,5],[1,2,3])." would evaluate to "true", or "take(3,[1,2,3,4,5],Ys)." would give "Ys = [1,2,3]", while "take(3,[1,2],Ys)" would give "Ys = [1,2]"
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