PROBLEMS (P NO: 330) hen the Two-Wattmeter Method is used to measure the Input Power of a balanced load, the readings on the wattmeters are 7.5 KW and 2.5 KW. The connections to one of the coils on the meter reading 2.5 KW, have been reversed. Determine the: (a) Total Input Power, and (b) Load Power Factor. (a) 5 KW (b) 0.277]

The data of the power system shown in the figure: X= 1.2 p.u. X= 0.15 p.u. 20MVA G1, G2, G3: T, Т, Тз: L1, L2, L3, L4: Ls: Draw the reactance diagram marked on it all the reactance's in per-unit. 11 KV 30MVA 11/66 KV 66KV X= 400 66KV X= 202 T1 L (G1 T3 Ls L4 美 T2 G3 G2

At what p.f will one of the wattmeter reading be zero in a three-phase system. Please answer this in detail

Voltage and current of a three – phase load are as follows: Voltage: 3.6 kV, 8 degrees Current: 37 A, 45 degrees What is the power factor of this load?

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A three – phase load with 1.8 1.7 MVA and 0.92 0.85 leading power factor is connected to a 13.47 kV grid. What is the magnitude of the current of this load in Ampere?

using zero power factor potier methode

1. Which of the following applies to the instantaneous power in a single-phase ac circuit? A. Constant component B. Time varying component O C. Frequency of time varying component is twice the voltage or current D. All of these

26. In a two wattmeter method of power measurement of a balanced load,  wattmeter readings are -66.8 kW and  -16.8 kW. The reversing switch is operated in the first wattmeter showing -66.8 kW. find (a) total input power and (b) load power factor.

i need the answer quickly