Problem le Capactive impedance WC JXL= jwL Vs. bcos (100t+35°) =6235°V > lasin (1004 + 35') = 12 cos(100++35°-90°) = 12 2-65° V W = 100 rad/sec jx300j100x300x 0.001 =j30 jxnoo =j100 x 400 x 0.001 = √40 jx200 = 3100 x 200+ 0.001 jxe= = jao 100x Sox 10 = -200 50~ 400 m H + лик VSI 300MH 200H aroar 3702 j40 jao Given circut www 70- 3j30 jaoo + Vsa node Vi V₁-V V₁ j40 J30 + + VI-6235' So j = O V₁ (- -)+ V = 435° U, (0.02-0.0583) + jo.025 v.0.0983+ 83+0.06883 - 1 Node Vo Vo-V₁ Vo + j40 200 + Vo-V₁ j40 V.-124-650 70+ jao =0 Vo Vo 122-650 + + -j200 70+ jao V₁ j40 +Volot j + 10-;20 122-650 200 7027 20° 72.801215.94 0.0250, + V. (0.0132-10.02377) = 0.1641-80.94° jooasv, +vo l0.0132 - j0,02377) = 0.026 - j0.163-2 Vo7.820-3.032 = 7.642-23.36 Vo=7647 cos (100+-23.36°
Problem le Capactive impedance WC JXL= jwL Vs. bcos (100t+35°) =6235°V > lasin (1004 + 35') = 12 cos(100++35°-90°) = 12 2-65° V W = 100 rad/sec jx300j100x300x 0.001 =j30 jxnoo =j100 x 400 x 0.001 = √40 jx200 = 3100 x 200+ 0.001 jxe= = jao 100x Sox 10 = -200 50~ 400 m H + лик VSI 300MH 200H aroar 3702 j40 jao Given circut www 70- 3j30 jaoo + Vsa node Vi V₁-V V₁ j40 J30 + + VI-6235' So j = O V₁ (- -)+ V = 435° U, (0.02-0.0583) + jo.025 v.0.0983+ 83+0.06883 - 1 Node Vo Vo-V₁ Vo + j40 200 + Vo-V₁ j40 V.-124-650 70+ jao =0 Vo Vo 122-650 + + -j200 70+ jao V₁ j40 +Volot j + 10-;20 122-650 200 7027 20° 72.801215.94 0.0250, + V. (0.0132-10.02377) = 0.1641-80.94° jooasv, +vo l0.0132 - j0,02377) = 0.026 - j0.163-2 Vo7.820-3.032 = 7.642-23.36 Vo=7647 cos (100+-23.36°
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...
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Question
Use mesh method to calculate vo(t) = Xcos (100t + Y) in the given circuit, where Y is thephase in radians. Find X and Y. Us1 (t) = 6 cos(100t + 35º) and Vs2 (t) = 12 sin(100t + 35º) Need help seeing if i did the problem correct
Transcribed Image Text:Problem le
Capactive impedance
WC
JXL= jwL
Vs. bcos (100t+35°)
=6235°V
> lasin (1004 +
35')
= 12 cos(100++35°-90°)
= 12 2-65° V
W = 100 rad/sec
jx300j100x300x 0.001
=j30
jxnoo =j100 x 400 x 0.001
= √40
jx200 = 3100 x 200+ 0.001
jxe=
= jao
100x Sox 10
= -200
50~
400 m H
+
лик
VSI
300MH
200H
aroar
3702
j40
jao
Given circut
www
70-
3j30
jaoo
+
Vsa
node Vi
V₁-V
V₁
j40
J30
+
+ VI-6235'
So
j
= O
V₁ (- -)+ V = 435°
U, (0.02-0.0583) + jo.025 v.0.0983+
83+0.06883 - 1
Node Vo
Vo-V₁
Vo
+
j40
200
+
Vo-V₁
j40
V.-124-650
70+ jao
=0
Vo
Vo
122-650
+
+
-j200
70+ jao
V₁
j40
+Volot
j
+
10-;20
122-650
200
7027 20°
72.801215.94
0.0250, + V. (0.0132-10.02377) = 0.1641-80.94°
jooasv, +vo l0.0132 - j0,02377) = 0.026 - j0.163-2
Vo7.820-3.032
= 7.642-23.36
Vo=7647 cos (100+-23.36°
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