Problem le Capactive impedance WC JXL= jwL Vs. bcos (100t+35°) =6235°V > lasin (1004 + 35') = 12 cos(100++35°-90°) = 12 2-65° V W = 100 rad/sec jx300j100x300x 0.001 =j30 jxnoo =j100 x 400 x 0.001 = √40 jx200 = 3100 x 200+ 0.001 jxe= = jao 100x Sox 10 = -200 50~ 400 m H + лик VSI 300MH 200H aroar 3702 j40 jao Given circut www 70- 3j30 jaoo + Vsa node Vi V₁-V V₁ j40 J30 + + VI-6235' So j = O V₁ (- -)+ V = 435° U, (0.02-0.0583) + jo.025 v.0.0983+ 83+0.06883 - 1 Node Vo Vo-V₁ Vo + j40 200 + Vo-V₁ j40 V.-124-650 70+ jao =0 Vo Vo 122-650 + + -j200 70+ jao V₁ j40 +Volot j + 10-;20 122-650 200 7027 20° 72.801215.94 0.0250, + V. (0.0132-10.02377) = 0.1641-80.94° jooasv, +vo l0.0132 - j0,02377) = 0.026 - j0.163-2 Vo7.820-3.032 = 7.642-23.36 Vo=7647 cos (100+-23.36°

Problem le Capactive impedance WC JXL= jwL Vs. bcos (100t+35°) =6235°V > lasin (1004 + 35') = 12 cos(100++35°-90°) = 12 2-65° V W = 100 rad/sec jx300j100x300x 0.001 =j30 jxnoo =j100 x 400 x 0.001 = √40 jx200 = 3100 x 200+ 0.001 jxe= = jao 100x Sox 10 = -200 50~ 400 m H + лик VSI 300MH 200H aroar 3702 j40 jao Given circut www 70- 3j30 jaoo + Vsa node Vi V₁-V V₁ j40 J30 + + VI-6235' So j = O V₁ (- -)+ V = 435° U, (0.02-0.0583) + jo.025 v.0.0983+ 83+0.06883 - 1 Node Vo Vo-V₁ Vo + j40 200 + Vo-V₁ j40 V.-124-650 70+ jao =0 Vo Vo 122-650 + + -j200 70+ jao V₁ j40 +Volot j + 10-;20 122-650 200 7027 20° 72.801215.94 0.0250, + V. (0.0132-10.02377) = 0.1641-80.94° jooasv, +vo l0.0132 - j0,02377) = 0.026 - j0.163-2 Vo7.820-3.032 = 7.642-23.36 Vo=7647 cos (100+-23.36°

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...

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