Problem: A refrigeration system employs one compressor-two evaporator system. One evaporator has a capacity of 7.5 tons at a temperature of -30°C, and the other evaporator at 10 tons operated at -20°C. The condensing temperature is 50°C. Determine the COP and the refrigerating efficiency of the system. od d 82 999 999 600 550 500 450 00 350 300 250 200 20 100 500 kg 900 1000 1050 1100 1150- 150 R-134a 1200 oggi 1300 20 10 by So opte pe 002 100 0€ 004 FOSEL -10: -20 -30 1400- -40°C 1450 N 09 18 8 ܘ ܚ ܐ ܙ X 0.2 8 180 170 T-160°C 150 140 130 120 110 100 90 80 70: PRESSURE, MPa 00 CONDENSER EVAP-1 EVAP-1 09 40- OC 20 10 -40 04- 0.02 0.01 600 550 Based on formulation of Ther-Ram and (1994) 500 -2.30 King-K 10 1.70- 1.60 1.50 OP 1.40- 8-1.30- 20- 1.10- 1.00- -0.90- 0.80 450 7.0 150 Properties computed with NIST REFPROP 100 0.01 0.2 0.02 400 350 ENTHALPY, kJ/kg Fig. 8 Pressure-Enthalpy Diagram for Refrigerant 134a 300 250 200 COMPRESSOR

Elements Of Electromagnetics
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8
EVAP-1
EVAP-1
CONDENSER
COMPRESSOR
5
PRESSURE, MPa
100
20
10
8
150
R-134a
(1.1.1.2-urethane)
2000 kg 100 kg-K)
2
Reference state
3.0 pen pages
D
09-
0.2
0.02
0.01
100
150
Properties computed with: NIST REFPROP
version 7.0
-50 1450
-30 1400
-40°C
-10
0.70
0.80:
pentry peptunes
1350-
060
200
-00
17
200
1300
60
250
_os_1,
04-
40-
$0
8-00
1.10-
-1.20
8-1.30-1
1150-
1200
8
8
1.40-
300
-0.6
TO
1.50-
1100
07
1050
8
1.60-
350
1000
0.8.
1.70-
60
28 8
006
Face
Saturnier
400
10
20
OC
450
40-
50-
250
300
350
400
ENTHALPY, kJ/kg
Fig. 8 Pressure-Enthalpy Diagram for Refrigerant 134a
09
10:
450
70:
09
06
220
500
500 kg/m²
400
100
110:
120
006
550
8=2.30 k
150
30 karka-k
100
80
60.
130-
140
150
T-160°C-
170-
180
A
8
20
efficiency of the system.
Problem:
50°C. Determine the COP and the refrigerating
at a temperature of -30°C, and the other evaporator at 10 tons operated at -20°C. The condensing temperature is
A refrigeration system employs one compressor-two evaporator system. One evaporator has a capacity of 7.5 tons
35
88
7-8-
0.04
0.02
0.01
500
550
600
Based on formulation of Tiner-Roth and Bar (1994)
1.0
8--8-
O
O
600
0,40
4
2
0.2
Transcribed Image Text:8 EVAP-1 EVAP-1 CONDENSER COMPRESSOR 5 PRESSURE, MPa 100 20 10 8 150 R-134a (1.1.1.2-urethane) 2000 kg 100 kg-K) 2 Reference state 3.0 pen pages D 09- 0.2 0.02 0.01 100 150 Properties computed with: NIST REFPROP version 7.0 -50 1450 -30 1400 -40°C -10 0.70 0.80: pentry peptunes 1350- 060 200 -00 17 200 1300 60 250 _os_1, 04- 40- $0 8-00 1.10- -1.20 8-1.30-1 1150- 1200 8 8 1.40- 300 -0.6 TO 1.50- 1100 07 1050 8 1.60- 350 1000 0.8. 1.70- 60 28 8 006 Face Saturnier 400 10 20 OC 450 40- 50- 250 300 350 400 ENTHALPY, kJ/kg Fig. 8 Pressure-Enthalpy Diagram for Refrigerant 134a 09 10: 450 70: 09 06 220 500 500 kg/m² 400 100 110: 120 006 550 8=2.30 k 150 30 karka-k 100 80 60. 130- 140 150 T-160°C- 170- 180 A 8 20 efficiency of the system. Problem: 50°C. Determine the COP and the refrigerating at a temperature of -30°C, and the other evaporator at 10 tons operated at -20°C. The condensing temperature is A refrigeration system employs one compressor-two evaporator system. One evaporator has a capacity of 7.5 tons 35 88 7-8- 0.04 0.02 0.01 500 550 600 Based on formulation of Tiner-Roth and Bar (1994) 1.0 8--8- O O 600 0,40 4 2 0.2
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