College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Question

can you solve part (a) & (b)?

 

Problem 4: A 15.9 g ball is moving at 27.2 m/s to the right as shown. It |collides with a 499 g sphere of clay that is suspended from a string. The ball sticks in the clay and the two of them swing on the string until they reach a maximum height h. m M h Part (a) Find the height h in m. Part (b) In the space below, show your work for part (a). Start with an equation or equations from the equation sheet and show your steps to the point where you would calculate the result. Max characters allowed 3000. 0/3000
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Transcribed Image Text:Problem 4: A 15.9 g ball is moving at 27.2 m/s to the right as shown. It |collides with a 499 g sphere of clay that is suspended from a string. The ball sticks in the clay and the two of them swing on the string until they reach a maximum height h. m M h Part (a) Find the height h in m. Part (b) In the space below, show your work for part (a). Start with an equation or equations from the equation sheet and show your steps to the point where you would calculate the result. Max characters allowed 3000. 0/3000
Expert Solution
Check Mark
Step 1

Let's use the conservation of momentum to find the final velocity of the two masses,

Initial momentum = Final momentum

mv1=(m+M)v2v2=mv1(m+M)m=15.9×10-3 kg, v1=27.2 m/s,M=499×10-3kg =15.9×10-3 kg×27.2 m/s15.9×10-3 kg+499×10-3kg v2=0.84 m/s

Step 2

The kinetic energy is converted into gravitational potential energy.

12m+Mv22=m+Mgh12v22=ghv222g=h=0.8422×9.8h=0.036 m=3.6×10-2m

 

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