Vector u = <-7,3,5> and vector v = <-1,1,0>. Find (vector u+v) X vector v.

Vector A = 7.2 i + 2.6 j. Vector B = 7.5 i + 7.4 j. The magnitude of the cross product i.e. |AxB| is: :

Vector A = (8, 4, -5) and Vector B = (-2, 3, 0). Find the angle between these two vectors.

Three points, A, B, and C, exist on an XY-plane. The positions of points A and B are (3,1) and (1,-1) respectively. The position of point C is (-1, 3).  Determine the position vector from point A to point C.  Determine the unit vector for this position vector.

These are the component forms of vectors u and w: ū u = (1, 1) w = (2,4) Subtract the vectors. ū - w = ][

For the given vectors V₁ and V2, determine V₁ + V2, V₁ + V2, V₁-V2, V1X V2, V₂ X V₁, and V₁ V₂. Consider the vectors to be nondimensional. V₂ = 11 Answers: V₁ + V₂ = V₁ + V₂ = V₁-V₂= V₁x V₂ = V₂X V₁ = V₁ V₂ = 69° i i i i i i 4 3 V₁ = 13 i+ i i+ i+ i i i+ i j+ i j+ i i k k k k

Vector A = 4.5 i+ 3.2 j. Vector B = 4.5 i + 4.2 j. The dot product of the two %3D is C = A•B (i.e. A dot B). The value of C is:

Vector C can be written (-3i+1j) cm O (-4i+2j) cm O (i-3j) cm (2i+-4j) cm 1 y (cm) 2 1 x (cm)

Vector u = <-7,3,-5> and vector v = <-1,1,0>. Find u X (-9v)

Find the area of the triangle determined by the points P, Q, and R. Find a unit vector perpendicular to plane PQR. Р(- 1,1, - 2), Q(-2,0,1), R(0, -2, - 1)