An object with a height of -0.070 m points below the principal axis (it is inverted) and is 0.140 m in front of a diverging lens. The focal length of the lens is -0.29 m. (Include the sign of the value in your answers.)

An object is placed 27 cm in front of a diverging lens having a focal length of magnitude 50 cm. What is the image distance, in cm?  Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.

The distance between the eyepiece and the objective lens in a certain compound microscope is 19.0 cm. The focal length of the eyepiece is 2.45 cm and that of the objective is 0.395 cm. What is the overall magnification of the microscope? dditi

= 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2

Homework 12 Problem 10:   Two lenses are mounted d = 27 cm apart on an optical bench. The focal length of the first lens is f1 = 5.1 cm and that of the second lens is f2 = 4.4 cm. An object of height ho = 3.5 cm is placed at a distance of do = 21 cm in front of the first lens. Part (a)  Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di = ______ Part (b)  Calculate the magnification of that image, including its sign. m = ______ Part (c)  Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D = ______

An object is 6 cm in front of a converging lens with a focal length of 10cm. Draw a ray diagram (to scale with a ruler) to find the location of the image. Is the image upright or inverted, and Is the image real or virtual? Then I want to use the thin lens formula to find the image distance and the magnification. I got stuck in the middle of this problem and am confused. Thank you for the help!

The projection lens in a certain slide projector is a single thin lens. A slide 24.5 mm high is to be projected so that its image fills a screen 1.77 m high. The slide-to-screen distance is 2.93 m. (a) Determine the focal length of the projection lens. mm (b) How far from the slide should the lens of the projector be placed to form the image on the screen? mm

Two lenses are placed along the x axis, with a diverging lens of focal length -8.70 cm on the left and a converging lens of focal length 17.0 cm on the right. When an object is placed 16.0 cm to the left of the diverging lens, what should the separations of the two lenses be if the final image is to be focused at x = 00? cm Submit Answer

A 7.75 mm high chocolate chip is placed on the axis of, and 13.9 cm from, a lens with a focal length of 6.91 cm. If it can be determined, is the chocolate chip's image real or virtual? virtual real cannot be determined How high is the image? Express the answer as a positive quantity. image height: mm

Find the image distance for a diverging lens of focal length magnitude |f|=10cm for an object located a distance of 13cm in front of the lens.  Find the magnification of the image in problem. Describe the image in problem.