(17%) Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function:{ x(t) = 3 + 5t + 2t2 + 0.4t3, y(t) = 0, z(t) = 0 }where t is in seconds and x in meters. can you help with parts b-e? Class Management I HelpHomework Week 2 Begin Date: 1/17/2022 12:01:00 AM -- Due Date: 1/27/2022 11:59:00 PM End Date: 5/6/2022 11:59:00 PM(17%) Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function:{ x(t) = 3 + 5t + 2? + 0.4, y(t) = 0, z(t) = 0 }where t is in seconds and x in meters.20% Part (a) True or False: the acceleration of the car is constant?FalseV Correct!> * 20% Part (b) Find the acceleration, in meters per square second, in the x-direction at t1 = 0.35 sec.Grade Summarya(t1) = 5.01|Deductions0%Potential100%sin()cos()tan()78.9HOMESubmissionscotan()asin()E 1^A456.Attempts remaining:(0% per attempt)acos()atan()acotan()sinh()123detailed viewcosh()Degreestanh()cotanh()END-10%RadiansVol BACKSPACECLEARDELSubmitHintFeedbackI give up!Hints: 1 for a 0% deduction. Hints remaining: 0Feedback: 0% deduction per feedback.|-The acceleration is the second time derivative of the displacement.A 20% Part (c) Find the acceleration, in meters per square second, in the x-direction at t = 1.35 sec.A 20% Part (d) Find the average velocity, in meters per second, in the x-direction between t = 0.35 s and t2 = 1.35 s.A 20% Part (e) Find the average acceleration, in meters per second squared, in the x-direction between t = 0.35 s and t2 = 1.35 s.

Given: x(t) = 3+5t+2t2+0.4t3y(t) = 0z(t) = 0

Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function: { x(t) = 3 + 5t + 2t2 + 0.4t3, y(t) = 0, z(t) = 0 } where t is in seconds and x in meters. can you help with parts b-e?

Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function: { x(t) = 3 + 5t + 2t2 + 0.4t3, y(t) = 0, z(t) = 0 } where t is in seconds and x in meters. can you help with parts b-e?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 40P

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Scalars and Vectors

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Question

(17%) Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function:

{ x(t) = 3 + 5t + 2t² + 0.4t³, y(t) = 0, z(t) = 0 }

where t is in seconds and x in meters.

can you help with parts b-e?

Class Management I Help
Homework Week 2 Begin Date: 1/17/2022 12:01:00 AM -- Due Date: 1/27/2022 11:59:00 PM End Date: 5/6/2022 11:59:00 PM
(17%) Problem 3: A car moves on a straight road such that its position from a reference point is given by the following function:
{ x(t) = 3 + 5t + 2? + 0.4, y(t) = 0, z(t) = 0 }
where t is in seconds and x in meters.
20% Part (a) True or False: the acceleration of the car is constant?
False
V Correct!
> * 20% Part (b) Find the acceleration, in meters per square second, in the x-direction at t1 = 0.35 sec.
Grade Summary
a(t1) = 5.01|
Deductions
0%
Potential
100%
sin()
cos()
tan()
7
8.
9
HOME
Submissions
cotan()
asin()
E 1^A
4
5
6.
Attempts remaining:
(0% per attempt)
acos()
atan()
acotan()
sinh()
1
2
3
detailed view
cosh()
Degrees
tanh()
cotanh()
END
-
1
0%
Radians
Vol BACKSPACE
CLEAR
DEL
Submit
Hint
Feedback
I give up!
Hints: 1 for a 0% deduction. Hints remaining: 0
Feedback: 0% deduction per feedback.
|-The acceleration is the second time derivative of the displacement.
A 20% Part (c) Find the acceleration, in meters per square second, in the x-direction at t = 1.35 sec.
A 20% Part (d) Find the average velocity, in meters per second, in the x-direction between t = 0.35 s and t2 = 1.35 s.
A 20% Part (e) Find the average acceleration, in meters per second squared, in the x-direction between t = 0.35 s and t2 = 1.35 s.

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