College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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1.7 The Components of a Vector
A person starts from his home and walks the following distances: i) 200 m, due north i) 180 m, 30.0° W of N iii) 120m, due south.
How far is the person from his home?
O 236 m
O 260 m
O 253 m
O 90.0 m
O 295 m
Submit Answer
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304
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Transcribed Image Text:1.7 The Components of a Vector A person starts from his home and walks the following distances: i) 200 m, due north i) 180 m, 30.0° W of N iii) 120m, due south. How far is the person from his home? O 236 m O 260 m O 253 m O 90.0 m O 295 m Submit Answer Save for Later 304
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Can you please look at my work and tell me where I messed up on this question?

YouTube N WeBWork: S_RR... WebWork: S_RR...
Other
1.7 The Components of a Vector
A person starts from his home and walks the following distances: i) 200 m, due north ii) 180 m, 30.0° W of N iii) 120 m, due south.
How far is the person from his home?
O 236 m
O 253 m
O 90.0 m
O 260 m
O 295 m
Submit Answer
Save for Later
W
JUN
2
Bartender M Gmail
Practice
|||
tv
"A
$
expand button
Transcribed Image Text:YouTube N WeBWork: S_RR... WebWork: S_RR... Other 1.7 The Components of a Vector A person starts from his home and walks the following distances: i) 200 m, due north ii) 180 m, 30.0° W of N iii) 120 m, due south. How far is the person from his home? O 236 m O 253 m O 90.0 m O 260 m O 295 m Submit Answer Save for Later W JUN 2 Bartender M Gmail Practice ||| tv "A $
115⁰
in
1187
Ax,
N
ute
#1: i
मेने पे
300
717²7-1200m
X
1
i=200m i K80m iii = 120m
ix=0
We know this will be
necfativ!
Ho
200m
#2 iix (40) : Sino = # -> Sin OH = Ha(iix) -> Sin (30°) 180m = iix
WE GDCD lixe = 90
TORON
iix = -90
1+ 3 iiy (H₂): Cos Ⓒ - + -D Cos (30°) (180m) = 155m | 1xy = 155 m
O
#ul
iiix = 0
#5y2 -120
x= √ (ix +iix +iiix ) = ( ¡y +iiy tiiiy
-D
J₂ -> x=√ (0+ (-90) +0) ³² + (200 + 155 + (-120)?
x= √(-90)² + (235)² -> x= √√-7865+55325
X> √47360 = x=217.6m
= 12.3
S
iix
Deo.
0+ (-90) +
expand button
Transcribed Image Text:115⁰ in 1187 Ax, N ute #1: i मेने पे 300 717²7-1200m X 1 i=200m i K80m iii = 120m ix=0 We know this will be necfativ! Ho 200m #2 iix (40) : Sino = # -> Sin OH = Ha(iix) -> Sin (30°) 180m = iix WE GDCD lixe = 90 TORON iix = -90 1+ 3 iiy (H₂): Cos Ⓒ - + -D Cos (30°) (180m) = 155m | 1xy = 155 m O #ul iiix = 0 #5y2 -120 x= √ (ix +iix +iiix ) = ( ¡y +iiy tiiiy -D J₂ -> x=√ (0+ (-90) +0) ³² + (200 + 155 + (-120)? x= √(-90)² + (235)² -> x= √√-7865+55325 X> √47360 = x=217.6m = 12.3 S iix Deo. 0+ (-90) +
Solution
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Follow-up Questions
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Follow-up Question

Can you please look at my work and tell me where I messed up on this question?

YouTube N WeBWork: S_RR... WebWork: S_RR...
Other
1.7 The Components of a Vector
A person starts from his home and walks the following distances: i) 200 m, due north ii) 180 m, 30.0° W of N iii) 120 m, due south.
How far is the person from his home?
O 236 m
O 253 m
O 90.0 m
O 260 m
O 295 m
Submit Answer
Save for Later
W
JUN
2
Bartender M Gmail
Practice
|||
tv
"A
$
expand button
Transcribed Image Text:YouTube N WeBWork: S_RR... WebWork: S_RR... Other 1.7 The Components of a Vector A person starts from his home and walks the following distances: i) 200 m, due north ii) 180 m, 30.0° W of N iii) 120 m, due south. How far is the person from his home? O 236 m O 253 m O 90.0 m O 260 m O 295 m Submit Answer Save for Later W JUN 2 Bartender M Gmail Practice ||| tv "A $
115⁰
in
1187
Ax,
N
ute
#1: i
मेने पे
300
717²7-1200m
X
1
i=200m i K80m iii = 120m
ix=0
We know this will be
necfativ!
Ho
200m
#2 iix (40) : Sino = # -> Sin OH = Ha(iix) -> Sin (30°) 180m = iix
WE GDCD lixe = 90
TORON
iix = -90
1+ 3 iiy (H₂): Cos Ⓒ - + -D Cos (30°) (180m) = 155m | 1xy = 155 m
O
#ul
iiix = 0
#5y2 -120
x= √ (ix +iix +iiix ) = ( ¡y +iiy tiiiy
-D
J₂ -> x=√ (0+ (-90) +0) ³² + (200 + 155 + (-120)?
x= √(-90)² + (235)² -> x= √√-7865+55325
X> √47360 = x=217.6m
= 12.3
S
iix
Deo.
0+ (-90) +
expand button
Transcribed Image Text:115⁰ in 1187 Ax, N ute #1: i मेने पे 300 717²7-1200m X 1 i=200m i K80m iii = 120m ix=0 We know this will be necfativ! Ho 200m #2 iix (40) : Sino = # -> Sin OH = Ha(iix) -> Sin (30°) 180m = iix WE GDCD lixe = 90 TORON iix = -90 1+ 3 iiy (H₂): Cos Ⓒ - + -D Cos (30°) (180m) = 155m | 1xy = 155 m O #ul iiix = 0 #5y2 -120 x= √ (ix +iix +iiix ) = ( ¡y +iiy tiiiy -D J₂ -> x=√ (0+ (-90) +0) ³² + (200 + 155 + (-120)? x= √(-90)² + (235)² -> x= √√-7865+55325 X> √47360 = x=217.6m = 12.3 S iix Deo. 0+ (-90) +
Solution
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