Problem #2: Determine the force in each member of the loaded truss (state if the members are in tension (T) or compression (C)). Make use of the symmetry of the truss and of the loading.
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- Find the force acting in each of the members of the truss shown below. Remember to specify if each member is in tension or compression. 6 ft - 6 ft 6 ft 500 lbs 6 ftThe Figure shown below is the truss patten proposed by engineering students for the one part of modern houses. Reaction forces for both pin A and roller F have already been calculated. a H D 12 f1 6 ft A, = 0 45° 45° F B E 6 It 6 ft 6 t 6 ft -- 6 f1 - A, = 3 k 3k 3k F, = 3k a) By using appropriate methods calculate all determinable forces in the members and define whether the members are in tension or compression. b) Is there any zero-force member? If no add 2 to get more stable design. c) As we know, the bridges of long structure tend to elongate under the impact of thermal stress. Which design should be preferred for this case, and why?For Probs. 1-3, (a) draw the free-body diagrams for the entire assembly (or structure) and each of its parts. Neglect friction and the weights of the members unless specified otherwise. Be sure to indicate all relevant dimensions. For each problem, (b) determine the total number of unknown forces and the total number of independent equilibrium equations. Problem 1 500 N 500 N 1 m 500 N (b) (c) Figure 1 Problem 2 -- Ift 4 ft -1.8 ft 100 lb F1.8 ft - 100 lb 100 lb (а) (b) (c)
- Statics, Find the force in member BC, BE, and EF of the truss and state if the members are in Tension or Compression, given :P1 = 95 kN, P2=75 kN, P3=85 kN, L1=3 m, L2=5 m(Use positive values to indicate Tension and negative values to indicate Compression)4/6- Frames & Machines / Charpente et Mécanisme Sample Problem / Exemple (4-6) The frame supports the 400-kg load in the manner shown. Neglect the weights of the members compared with the forces induced by the load and compute the horizontal and vertical components of all forces acting on each of the members. ↑ 1.5 m 0.5 m Тв 1.5 m 1.5 m ✓ C A 3 m -2 m E F 0.5 m 400 kg La structure supporte une charge de 400 kg de la façon représentée. Négligez les poids des barres par rapport aux forces développées par la charge et calculez les composantes horizontales et verticales de toutes les forces qui agissent sur chacune des barres.Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 5.0 m Answers: BC- BE- A 5.0 m EF= i i i B 5.0 m 5.0 m C 20.5 KN 5.0 m 3.4 m 3 3 3 KN D
- Calculate the force in member GH of the truss and indicate whether it is in tension or compression, using either method of joints or method of sections. Required: Draw the FBD(s) as needed for analysis-all equilibrium equations must correspond to a FBD that you have drawn. Make sure to clearly indicate which FBD your equation(s) correspond to. K J H 4 ft C - 3 ft 3 ft -- 3 ft- 3 ft-3 ft 1500 lb 1500 lb 1500 lb 1500 lb 1500 lbThe light boom AB is attached to a vertical wall by a ball and socket joint at A and supported by two cables at B.A force P is applied at B where P= 20i - 14j kN.Note that the reaction force at A acts along the boom because it is a two-force member. Calculate the magnitude of the reaction force at A in kN. of stion 2m 4 m. 6 m Answer: 5 Calculate the magnitude of the tension in cable BD in kN. of Answer:1. Use the METHOD OF SECTIONS to determine the forces in members AC, BC, and BD of the truss in Figure 1 and indicate whether each of these members is in tension or compression. As usual, show any free-body diagram(s) (including all essential components), and clearly annotate all calculations. Note: You may use the support reactions calculated in Tutorial S2, Problem 3 without repeating the necessary calculations. А C 220° 1 m 25 KN В 1 m 1 m Figure 1. [ans.: FAC = 51.29 kN (tension); FBC = -22.73 kN (comp); FBD = -16.07 kN (comp)]
- A rear suspension system for a front wheel-drive vehicle is shown here. Spring EF is offset behind member CD. The normal force due to contact between 2 wheel and the road is 4200 N. Assume the weight of the wheel and suspension system components is negligible. (a) Determine the magnitude of the force in member CD. Is the member in tension or compression? (b) Determine the support reactions at A. (c) Determine the unstretched length of the spring EF given a spring constant of 150 kN/m. 60 mm 1130 mm 60 mm 245 mm D 220 mm F 260 mm E B 165 mm 90 mm F = 4200 N1. The force in the strut AB 2. the horizontal component at the pin C 3. the vertical component at the pin C Please include a freebody diagram, proper solution, proper symbols and force directions.Problem 2. From the figure below, Given: weight of the cylinder= 350 KN Note: neglect the weight of the bar and friction 350 kN 3m 10.5 m 258 25 40B a. Compute the reaction at A b. Compute the reaction at D c. Compute the tension in cable at B