Problem #2 A beam having a simple span of 4.2 m. carries a concentrated service live load P at its midspan. The beam is made up of a channel section. Assume that the load is applied through the shear center so that there is no torsional loading. Assume lateral loads are applied at both ends only. Prop. of channel section d = 457.2 mm tr = 15.875 mm Sx = 1141 x 103 mm3 ly = 6.785 x 106 mm4 U = 1.2 DL + 1.6 LL ® Determine the nominal flexural strength of the channel using LRFD. Fy = 248 MPa E = 200000 MPa ® Determine the value of P that can be applied to the beam due to its flexural strength use LRFD. = 26.162 mm Lp = 1.307 L; = 5.341 ® Determine the value of P that can be applied to the beam due to its allowable bending stress using ASD. Cb = 1.32 Zx = 1430 x 103 mm3 Solution: Wt. of channel = 77 kg/m O Nominal flexural strength of channel using LRFD: Lo = 4.2 m 4.2 m

Problem #2 A beam having a simple span of 4.2 m. carries a concentrated service live load P at its midspan. The beam is made up of a channel section. Assume that the load is applied through the shear center so that there is no torsional loading. Assume lateral loads are applied at both ends only. Prop. of channel section d = 457.2 mm tr = 15.875 mm Sx = 1141 x 103 mm3 ly = 6.785 x 106 mm4 U = 1.2 DL + 1.6 LL ® Determine the nominal flexural strength of the channel using LRFD. Fy = 248 MPa E = 200000 MPa ® Determine the value of P that can be applied to the beam due to its flexural strength use LRFD. = 26.162 mm Lp = 1.307 L; = 5.341 ® Determine the value of P that can be applied to the beam due to its allowable bending stress using ASD. Cb = 1.32 Zx = 1430 x 103 mm3 Solution: Wt. of channel = 77 kg/m O Nominal flexural strength of channel using LRFD: Lo = 4.2 m 4.2 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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